Q2) For the Angle Modulated x.(t) = 10cos[2n × 10®t + 5sin(2n × 103t)] Choose the correct answer for TEN of the following 1) The Maximum Phase Deviation will be (a) 1 rad (b) 3 rad (c) 5 rad (d) 10 rad 2) The Maximum Frequency Deviation will be (a) 2 kHz (b) 5 kHz (c) 12 kHz (d) 24 kHz 3) Average Power of the Angle Modulated Signal will be (a) 12.5 W (b) 50 W (c) 112.5 W (d) 200 W 4) The Modulation Index will be (a) 1 (b) 3 (c) 5 (d) 10
Q2) For the Angle Modulated x.(t) = 10cos[2n × 10®t + 5sin(2n × 103t)] Choose the correct answer for TEN of the following 1) The Maximum Phase Deviation will be (a) 1 rad (b) 3 rad (c) 5 rad (d) 10 rad 2) The Maximum Frequency Deviation will be (a) 2 kHz (b) 5 kHz (c) 12 kHz (d) 24 kHz 3) Average Power of the Angle Modulated Signal will be (a) 12.5 W (b) 50 W (c) 112.5 W (d) 200 W 4) The Modulation Index will be (a) 1 (b) 3 (c) 5 (d) 10
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![Q2) For the Angle Modulated
(20 Marks)
x.(t) = 10cos[2n x 10ºt + 5sin(2n × 103t)]
Choose the correct answer for TEN of the following
1)
The Maximum Phase Deviation will be
(а)
1 rad
(b)
3 rad
(c) 5 rad
(d)
10 rad
2)
The Maximum Frequency Deviation will be
(a) 2 kHz
(b)
5 kHz
(c)
12 kHz
(d)
24 kHz
3)
Average Power of the Angle Modulated Signal will be
(a)
12.5 W
(b) 50 W
(c)
112.5 W
(d) 200 W
4)
The Modulation Index will be
(a)
1
(b)
3
(c) 5
(d)
10
5) The Bandwidth will be
(a) 80 kHz
(b)
64 kHz
(c) 42 kHz
(d)
128 kHz
6)
If the Angle Modulated signal is PM and the modulating frequency is doubled, The
Bandwidth will be
(a)
80 kHz
(b)
64 kHz
(c) 42 kHz
(d)
128 kHz
7) If the Angle Modulated signal is FM and the modulating frequency is decreased by
one-half, The Bandwidth will be
(а)
80 kHz
(b)
64 kHz
(c) 42 kHz
(d)
128 kHz
8)
If the Angle Modulated signal is FM and the modulating frequency is doubled, The
Bandwidth will be
(a)
80 kHz
(b)
64 kHz
(c) 42 kHz
(d)
128 kHz
9)
If the Angle Modulated Signal is an FM with ke = 103t, then m(t) will be
(a)
48 t x 10 cos (16n x 10°t)
(b)
48 x 10 cos (16m x 10°t)
(c) 48 cos(16T x 103t)
(d) 48 t cos (16m x 10°t)
2-3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6ceac23d-2377-4e59-99c1-0afdb57490f0%2Fa13c60d9-1ed6-41a1-ad46-7cecddd3c768%2F02o2pd8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q2) For the Angle Modulated
(20 Marks)
x.(t) = 10cos[2n x 10ºt + 5sin(2n × 103t)]
Choose the correct answer for TEN of the following
1)
The Maximum Phase Deviation will be
(а)
1 rad
(b)
3 rad
(c) 5 rad
(d)
10 rad
2)
The Maximum Frequency Deviation will be
(a) 2 kHz
(b)
5 kHz
(c)
12 kHz
(d)
24 kHz
3)
Average Power of the Angle Modulated Signal will be
(a)
12.5 W
(b) 50 W
(c)
112.5 W
(d) 200 W
4)
The Modulation Index will be
(a)
1
(b)
3
(c) 5
(d)
10
5) The Bandwidth will be
(a) 80 kHz
(b)
64 kHz
(c) 42 kHz
(d)
128 kHz
6)
If the Angle Modulated signal is PM and the modulating frequency is doubled, The
Bandwidth will be
(a)
80 kHz
(b)
64 kHz
(c) 42 kHz
(d)
128 kHz
7) If the Angle Modulated signal is FM and the modulating frequency is decreased by
one-half, The Bandwidth will be
(а)
80 kHz
(b)
64 kHz
(c) 42 kHz
(d)
128 kHz
8)
If the Angle Modulated signal is FM and the modulating frequency is doubled, The
Bandwidth will be
(a)
80 kHz
(b)
64 kHz
(c) 42 kHz
(d)
128 kHz
9)
If the Angle Modulated Signal is an FM with ke = 103t, then m(t) will be
(a)
48 t x 10 cos (16n x 10°t)
(b)
48 x 10 cos (16m x 10°t)
(c) 48 cos(16T x 103t)
(d) 48 t cos (16m x 10°t)
2-3
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