Q2 Figure Q2 is a Reversed Carnot Cycle with a food department is kept at -12°C. The total heat gain to the food department is estimated to be 3300kJ/h and the heat rejection in the condenser is 4800KJ/h. Calculate i, the power input to the compressor in kW ii. The Coefficient of performance (COP)R of the Plant. TH = 30 QH =4800 Figure (Q2) R Went QL=3300 TL=-12 C °C
Q2 Figure Q2 is a Reversed Carnot Cycle with a food department is kept at -12°C. The total heat gain to the food department is estimated to be 3300kJ/h and the heat rejection in the condenser is 4800KJ/h. Calculate i, the power input to the compressor in kW ii. The Coefficient of performance (COP)R of the Plant. TH = 30 QH =4800 Figure (Q2) R Went QL=3300 TL=-12 C °C
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Q2 Figure Q2 is a Reversed Carnot Cycle with a food
department is kept at
-12°C. The total heat gain to the food department is estimated to be
3300kJ/h and the heat rejection in the condenser is 4800KJ/h. Calculate
i, the power input to the compressor in kW ii. The Coefficient of
performance (COP)R of the Plant.
TH = 30
QH =4800
Figure (Q2)
R
Went
QL=3300
TL=-12 C
°C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b51f220-ba96-46f0-869d-8c90c1cf63da%2Fb68ae22c-c363-4337-a146-81b291057021%2Fjmbapqk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q2 Figure Q2 is a Reversed Carnot Cycle with a food
department is kept at
-12°C. The total heat gain to the food department is estimated to be
3300kJ/h and the heat rejection in the condenser is 4800KJ/h. Calculate
i, the power input to the compressor in kW ii. The Coefficient of
performance (COP)R of the Plant.
TH = 30
QH =4800
Figure (Q2)
R
Went
QL=3300
TL=-12 C
°C
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