Q2: According to the followingfrequency distribution table and raw:dataFrequency Distribution TableRaw DataClassf585669636271827990-991456775777263789480-8970-7911665067476074576660-6915537471585554807050-5940-4926460516168647266Q2 (b): According to the above rawdata, the value of standard deviation* :(SD) is10.0322 O10.360110.6669none of all above O

Solution: n= 40 observation The sum of raw data is ∑x=2619 The square sum of raw data is…

Answered: Q2 (b): According to the above raw…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Q3: There is claim that the mean annual turnover rate of the 300 count bottle of B Aspirin is changed. Therefore a random sample of 33 is chosen that show the average is 10 and the standard deviation is 7. Use 0.05 significant level If the test statistics is -9, he claim mean is
Please answer #14
n a sample of 1313 randomly selected high school seniors, the mean score on a standardized test was 11911191 and the standard deviation was 167.0167.0. Further research suggests that the population mean score on this test for high school seniors is 10201020. Does the t-value for the original sample fall between minus−t 0.99t0.99 and t 0.99t0.99? Assume that the population of test scores for high school seniors is normally distributed. Question content area bottom Part 1 The t-value of tequals=enter your response here ▼ does does not fall between minus−t 0.99t0.99 and t 0.99t0.99 because t 0.99t0.99equals=enter your response here.
The IQ scores for a random sample of subjects with low lead levels in their blood and another random sample of subjects with high lead levels in their blood were collected. The statistics are summarized in the accompanying table. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) to (c) below. The test staustic IS 1.07. (Round to two decimal places as needed.) The P-value is 0.050. (Round to three decimal places as needed.) State the conclusion for the test. Y C P X Low Lead Level P₁ 81 91.33828 15.13046 High Lead Level 2 28 87.13859 9.90781 OA. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores. XB. Reject the null hypothesis. There is not sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores. OC. Reject…
Evaluate the followings: (a) P (z<?)=0.0918 (b)Z.40 (c)P(1.44<z<2.33) (d) Z.99 (e) P (z>?) = 0.6950, (f) within 1.35 standard deviations from the mean (it means P (-1.35<Z<1.35)).
The batteries from a certain manufacturer have a mean lifetime of 820 hours, with a standard deviation of 90 hours. Assuming that the lifetimes are normally distributed, complete the following statements. (a) Approximately ? 1090 hours. of the batteries have lifetimes between 550 hours and (b) Approximately 68% of the batteries have lifetimes between hours and hours. X
Per the Barron's report the average weeks unemployed is 21.5 (population mean) with a population standard deviation of 5 weeks and a sample of 55. In the next five questions we will be calculating the probability that the sample of 55 will provide a mean within 1 week of the population mean. What is the probability to 4 decimals for (x<20.5)? Use the rounded standard error of the mean in calculations.
The time taken by employees at Grace Floral shop to put a bouquet together has a normal distribution with mean 26.4 minutes and standard deviation .8 minutes. (i) Find the probability that an employee chosen at random takes between 24.6 and 27.8 minutes to put a bouquet together. [5] (ii) 12% of employees take more than t minutes to put a bouquet together. (ii) Find the value of t.
Apply Chebyshev’s rule with k = 3 to verify that at least 89% of the observations in any data set lie within three standard deviations to either side of the mean, that is, between x - 3s and x + 3s.
From a sample with n=36, the mean duration of a geyser's eruptions is 3.36 minutes and the standard deviation is 0.66 minutes. Using Chebychev's Theorem, determine at least how many of the eruptions lasted between 1.38 and 5.34 minutes. At least ( ? ) of the eruptions lasted between 1.38 and 5.34 minutes.

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Q2 (b): According to the above raw data, the value of standard deviation * :(SD) is 10.0322 10.3601 O 10.6669 O none of all above