Q2: A 100 lb, bear slowed down his kinetic energy by 500 lb. ft starting with 40 ft/s speed while his potential energy increased by 1500 lb. ft, starting from 30 ft height. How much his final speed? If g=32.2 ft/s², determine the final velocity, in ft/s.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Q2: A 100 lb, bear slowed down his kinetic energy by 500 lb. ft starting with 40 ft/s speed
while his potential energy increased by 1500 lbf. ft, starting from 30 ft height. How much
his final speed? If g=32.2 ft/s², determine the final velocity, in ft/s.
Transcribed Image Text:Q2: A 100 lb, bear slowed down his kinetic energy by 500 lb. ft starting with 40 ft/s speed while his potential energy increased by 1500 lbf. ft, starting from 30 ft height. How much his final speed? If g=32.2 ft/s², determine the final velocity, in ft/s.
Expert Solution
Step 1: Given data of the question

G i v e n space t h a t
w e i g h t space equals 100 space l b subscript f equals 100 space cross times 4.44822 space N equals 444.822 space N
K E equals 500 space l b subscript f space f t space equals 500 cross times 1.35582 equals 677.91 space J
P E equals 1500 space l b subscript f
h equals 30 space f t
g equals 32.2 space fraction numerator f t over denominator s squared end fraction equals 9.81 m over s squared
V subscript i equals 40 space fraction numerator f t over denominator s end fraction equals 12.2 space m over s

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