Q1/What will be displayed when you run the codes below? A) a= (16 4); b= [174 5); e=a (2) + b (4) B) a=0; while a< 20 aa+3; end disp (a) C) a = 1; b = 4; e = 2*a+b^2-a*b+b D) b = [2 47496 7]; e= [2 35 7); suml = 0; for k = 1:4 suml = sum1+b(c(k)); end sum1 E) b = 3; for k = 1:5 end Q2/What will be displayed when you run the codes belowi A » disp(3) > x = 1:4; disp(x) > y = 3-x; disp ([x; y]) ====→?
Q1/What will be displayed when you run the codes below? A) a= (16 4); b= [174 5); e=a (2) + b (4) B) a=0; while a< 20 aa+3; end disp (a) C) a = 1; b = 4; e = 2*a+b^2-a*b+b D) b = [2 47496 7]; e= [2 35 7); suml = 0; for k = 1:4 suml = sum1+b(c(k)); end sum1 E) b = 3; for k = 1:5 end Q2/What will be displayed when you run the codes belowi A » disp(3) > x = 1:4; disp(x) > y = 3-x; disp ([x; y]) ====→?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![Q1/What will be displayed when you run the codes below?
A)
a = [16 4);
b= [174 5);
c= a (2) + b (4)
B)
a= 0;
while a < 20
a=a+3;
end
disp (a)
C) a = 1; b = 4; e = 2*a+b^2-a*b+b
D) b = [2 474967];
c = [2 35 7);
sum1 = 0;
for k = 1:4
sum1 = sum1+b(c(k));
end
sum1
E) b = 3;
for k = 1:5
end
Q2/What will be displayed when you run the codes below?
A
» disp(3)
>x = 1:4; disp(x)
»y = 3-x; disp ([x; vl)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30498515-f08b-42dc-8c83-a713b80a9208%2F3dc47c28-3566-422a-b72b-f54ef6799296%2Fxh9yy4_processed.png&w=3840&q=75)
Transcribed Image Text:Q1/What will be displayed when you run the codes below?
A)
a = [16 4);
b= [174 5);
c= a (2) + b (4)
B)
a= 0;
while a < 20
a=a+3;
end
disp (a)
C) a = 1; b = 4; e = 2*a+b^2-a*b+b
D) b = [2 474967];
c = [2 35 7);
sum1 = 0;
for k = 1:4
sum1 = sum1+b(c(k));
end
sum1
E) b = 3;
for k = 1:5
end
Q2/What will be displayed when you run the codes below?
A
» disp(3)
>x = 1:4; disp(x)
»y = 3-x; disp ([x; vl)
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