Q1:ln a sample of 100 steel wires the average breaking strength is 50 kN, with a standard deviation of 2 kN. a. Find a 95% confidence interval for the mean breaking strength of this type of wire. b. Find a 99% confidence interval for the mean breaking strength of this type of wire. C. An engineer claims that the mean breaking strength is between 49.7 kN and 50.3 kN. With what level of confidence can this statement be made? d. How many wires must be sampled so that a 95% confidence interval specifies the mean breaking strength to within 20.3 kN? e. How many wires must be sampled so that a 99% confidence interval specifies the mean breaking strength to within +0.3 kN?

Q1:ln a sample of 100 steel wires the average breaking strength is 50 kN, with a standard deviation of 2 kN. a. Find a 95% confidence interval for the mean breaking strength of this type of wire. b. Find a 99% confidence interval for the mean breaking strength of this type of wire. C. An engineer claims that the mean breaking strength is between 49.7 kN and 50.3 kN. With what level of confidence can this statement be made? d. How many wires must be sampled so that a 95% confidence interval specifies the mean breaking strength to within 20.3 kN? e. How many wires must be sampled so that a 99% confidence interval specifies the mean breaking strength to within +0.3 kN?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: The average weight of an elephant is 6.42 tons with a standard deviation of 1.07 tons. Use the…

A: Given Mean=6.42 Standard deviation = 1.07 By Empirical rule

Q: A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the…

Q: Based on data from the 2000 Census the average age of a Baldwin County, Alabama resident is 39 years…

A: We have given that Population mean =39 Population standard deviation =22.6

Q: Calculate the margin of error for a 95% confidence interval for the population mean.

A: Given that the sample size is n = 32 Population SD = 5 At 95% confidence level, the critical value…

Q: statistics practitioner took a random sample of 41 observations from a population whose standard…

A: Formula :

Q: How many weeks of data must be samples for the company to get the information it desires

A: The objective of this question is to determine the sample size needed to estimate the average weekly…

Q: A statistics practitioner took a random sample of 43 observations from a population whose standard…

A: It is given that, Sample mean = 101. Population standard deviation, sigma is 20. The sample size, n…

Q: Use the empirical rule to solve the problem. 6) At one college, GPA's are normally distributed with…

A: According to the empirical rule,

Q: group of 894 women aged 70- 79 had their height and weight measured. The mean height was 159 cm with…

A: Given that a group of 894 women aged between 70 - 79. Mean height and their standard deviation of…

Q: #6 The AKC says that the average weight of Chihuahua dogs is 4.6 lbs. sample A veterinarian thinks…

A: 6) Let μ and σ denote respectively the population mean and standard deviation of the weight of…

Q: A particular fruit's weights are normally distributed, with a mean of 636 grams and a standard…

Q: (MMC 5.18) Flixable reports that Netflix's U.S. catalog contains almost 4000 movies. You are…

A: given : given population standard deviations of the length of movies =34 1): To find standard…

Q: A statistics practitioner took a random sample of 45 observations from a population whose standard…

A: Confidence interval is a part of interval estimation, which is used to estimate the unknown value of…

Q: . There is some reason to believe that the mean normal adult body temperature is not 98.6 degrees…

A: We want to test whether the mean normal adult body temperature is 98.6 F or not. Let μ denotes the…

Q: You are given the sample mean and the population standard deviation. Use this information to…

Q: According to a local newspaper, students at a local university usually take 4.5 years to graduate. A…

A: 1) Here the parameter is that average number of years required to graduate. Thus, μ=4.5 Claim: A…

Q: From previous studies, it has been generally believed that Northern Hemisphere icebergs have a mean…

A: From the given information, the Northern Hemisphere icebergs have a mean depth of 270 meters.

Q: You want to buy a washing machine, and a salesperson tells you that the mean repair costs for Model…

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Given,sample size(n)=77sample mean(x¯)=83.14population standard…

Q: Newborn babies: A study conducted by the Center for Population Economics at the University of…

Q: In a random sample of eight people, the mean driving distance to work was 21.7 miles and the…

A: Given that : Sample size (n) = 8 Sample mean = Standard deviation (s) = 7.4 Confidence interval is…

Q: In a survey 26 people where asked how much they spent on their child's birthday gift. The results…

A: We have given that Sample size=n=26 Mean=Xbar=50.9 Standard deviation=S=9.4 90% confidence interval…

Q: You want to find a 90% confidence interval for the mean height of students at your school. You…

A: Population standard deviation, sigma is 3.9. The z-critical value for 90% confidence interval is…

Q: A fitness center is interested in finding a 90% confidence interval for the mean number of days per…

A: It is given that sample mean is 2.2 and the standard deviation is 2.9.

Q: We want to compare cholesterol levels between men and women, so we collect a sample of 20 women and…

Q: Determine if one-tailed test or two-tailed test fits the given alternative hypothesis. 1. The mean…

A: Hypothesis : It is a statement about the parameter or statistical distribution that we have to…

Q: A fashion designer wants to know how many new dresses women buy each year. A sample of 650 women was…

A: From the provided information, Sample size (n) = 650 Population standard deviation (σ) = 1.3 Sample…

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

Q1:ln a sample of 100 steel wires the average breaking
strength is 50 kN, with a standard deviation of 2 kN.
a. Find a 95% confidence interval for the mean
breaking strength of this type of wire.
b. Find a 99% confidence interval for the mean
breaking strength of this type of wire.
C. An engineer claims that the mean breaking
strength is between 49.7 kN and 50.3 kN. With
what level of confidence can this statement be
made?
d. How many wires must be sampled so that a 95%
confidence interval specifies the mean breaking
strength to within 20.3 kN?
e. How many wires must be sampled so that a 99%
confidence interval specifies the mean breaking
strength to within 20.3 kN?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 5 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

A population has a mean of 15 and standard deviation of 3. Round the answers to two decimal places as needed. Part 1: Find the z-score for a population value of 2. The z-score for a population value of 2 is -4.33 Part 2: Find the z-score for a population value of 5. The z-score for a population value of 5 is -3.33 Part 3: What number has a z-score of 0.7?
A statistics practitioner took a random sample of 57 observations from a population whose standard deviation is 25 and computed the sample mean to be 103. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 95% confidence, changing the population standard deviation to 58; Confidence Interval = C. Estimate the population mean with 95% confidence, changing the population standard deviation to 7; Confidence Interval =
3- A previous analysis of paper boxes showed that the standard deviation of their lengths is 9 millimeters. A packer wishes to find the 96% confidence interval for the average length of a box. How many boxes does he need to measure to be accurate within 3 millimeters? Z.
A random sample of 93 observations produced a mean x = 25.5 and a standard deviation s 2.8. a. Find a 95% confidence interval for u. b. Find a 90% confidence interval for u. c. Find a 99% confidence interval for u.
A statistics practitioner took a random sample of 59 observations from a population whose standard deviation is 32 and computed the sample mean to be 95. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval= C. Estimate the population mean with 99% confidence. Confidence Interval=
3.3.16 EQuestion Help Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 32 and the age of the winner for best actress was 47. For all best actors, the mean age is 45.2 years and the standard deviation is 8.3 years. For all best actresses, the mean age is 33.7 years and the standard deviation is 12 5 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z = and the z score for the actress is z=, the V had the more extreme age (Round to two decimal places.)
A particular fruit's weights are normally distributed, with a mean of 515 grams and a standard deviation of 36 grams. The heaviest 13% of fruits weigh more than how many grams? Give your answer to the nearest gram. Enter an integer or decimal number [more..] Submit Question 2 Type here to search hp esc 12 fs 2 3 4 LO 远 %24 %23
Hi , please help me. Thank you.
Can someone answer this ? I need the averages and the standard deviations.
1. A recent study of 22 motorists showed that they spent an average of P750 per week. The standard deviation of the sample was P90. Find the 99% confidence interval of the true mean. Solution: 2. A sample of 15 National Collegiate Athletics Association (NCAA) basketball players had an average height of 6 feet with a sample standard deviation of 0.80 foot. Find the 90% confidence interval of the true mean height of all players. Solution:
A statistics class is estimating the mean height of all female students at their college. They collect a random sample of 42 female students and measure their heights. The mean of the sample is 65.3 inches and the sample standard deviation is 5.4 inches. Find the 90% confidence interval for the mean height of all female students in their school? Assume that the distribution of individual female heights at this school is approximately normal. 1. The t value is 1.3025 2. The standard error has a value of -- 3. The margin of error has a value of 4. Find the 90% confidence interval for the mean height of all female students in their school
A quiz related to digital knowledge was conducted. The quiz had 10 questions and covered topics such as the purpose of browser cookies, phishing scams, and privacy policies. The survey was given to 50 people. The mean score is 4.1 with a standard deviation of 2.6. We want to know if the data provide evidence that the mean score in the population is lower than 5. We will use alpha = 0.05 to make our decision. part a. Is this a one-sided or two-sided test? part b. What is the standard error for this problem? part c. How many degrees of freedom do we have for this problem? part d. What is the test statistic, t, for this problem? Based on your test statistic and degrees of freedom, the p-value will be between what two values? (If you cannot find the exact df in the table, round down to be safe. So if you have 38 df, round down to 30df.) Group of answer choices The p-value is between .1 and .05 The p-value is between .05 and .025 The p-value is between .025 and .01 The p-value…