Q18: Select the incorrect step while evaluating J x2-7x+10 dx. x-8 I: Let I = S- dx = S dx - S dx x2-7x+10 x2-7x+10 x2-7x+10 II: I =S; o dx – ; 2x-7+7 8 - S 2x-7 dx = ,J 2-7x+10 dx – 2 x2-7x+10 x2-7x+10 1 dxe J x2-7x+10 III: I = S dx - - 2х-7 1 zdx x2-7x+10 |x- IV:1 = log|Vx² – 7x + 10|– 3log| + Ce |x-2 (a) Only II- (b) Only III- (c) Only IV (d) All are correcte

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Related questions
Question
x-8
Q18: Select the incorrect step while evaluating J
-dx.
x2-7x+10
x-8
8
I: Let I = S
dx = S
dx - S
%3D
x2-7x+10
x2-7x+10
x2-7x+10
2x-7+7
8
II: I =;S
dx - S
2х-7
-dx –
dx =5J x2–7x+10
x2-7x+10
x2-7x+10
1
dx
x2-7x+10
2
dx -
2х-7
III: I = ;S
1
dx
(x-)-O
x2-7x+10
|x-
IV: 1 = log|Vx? – 7x + 10|– 3 log +Ce
+ Ce
x-
(a) Only II-
(b) Only III-
(c) Only IV
(d) All are correct
Transcribed Image Text:x-8 Q18: Select the incorrect step while evaluating J -dx. x2-7x+10 x-8 8 I: Let I = S dx = S dx - S %3D x2-7x+10 x2-7x+10 x2-7x+10 2x-7+7 8 II: I =;S dx - S 2х-7 -dx – dx =5J x2–7x+10 x2-7x+10 x2-7x+10 1 dx x2-7x+10 2 dx - 2х-7 III: I = ;S 1 dx (x-)-O x2-7x+10 |x- IV: 1 = log|Vx? – 7x + 10|– 3 log +Ce + Ce x- (a) Only II- (b) Only III- (c) Only IV (d) All are correct
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