Q16: Water is being pumped from the bottom of a well 150 ft deep at a rate of 50 gal/min through a pipe of 3.03 inch diameter, into an atmospheric storage tank 30 ft above the ground (water inside the well and in the storage tank are assumed stationary) A 2hp pump is used for pumping water, to prevent freezing in the winter a small heater added heat to water at a rate of 5000 Btu/min, total heat losses from the system3 1000 Btu/min. Calculate: - (A) The velocity ft/sec at which water is flowing through the pipe. (B) The total enthalpy change per min. Given that ge=32.17 lbm.ft/lbf.sec2 1 ft=12inch 1ft=7.48 gal pwater=62.4 lb/ft³ 1 Btu =252 Cal 1 Btu = 778 ft.lbf %3D 1 hp = 550 ft.lbf/sec

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question
I need the answer as soon as possible
Q16: Water is being pumped from the bottom of a well 150 ft deep at a rate of 50 gal/min
through a pipe of 3.03 inch diameter, into an atmospheric storage tank 30 ft above the
ground (water inside the well and in the storage tank are assumed stationary) A 2hp
pump is used for pumping water, to prevent freezing in the winter a small heater added
heat to water at a rate of 5000 Btu/min, total heat losses from the system= 1000
Btu/min.
Calculate: - (A) The velocity ft/sec at which water is flowing through the pipe.
(B) The total enthalpy change per min.
Given that go=32.17 lbm.ft/lbf.sec2
1 ft=12inch
1ft=7.48 gal
pwater=62.4 lb/ft
1 Btu =252 Cal
1 Btu = 778 ft.lbf
1 hp = 550 ft.lbf/sec
Transcribed Image Text:Q16: Water is being pumped from the bottom of a well 150 ft deep at a rate of 50 gal/min through a pipe of 3.03 inch diameter, into an atmospheric storage tank 30 ft above the ground (water inside the well and in the storage tank are assumed stationary) A 2hp pump is used for pumping water, to prevent freezing in the winter a small heater added heat to water at a rate of 5000 Btu/min, total heat losses from the system= 1000 Btu/min. Calculate: - (A) The velocity ft/sec at which water is flowing through the pipe. (B) The total enthalpy change per min. Given that go=32.17 lbm.ft/lbf.sec2 1 ft=12inch 1ft=7.48 gal pwater=62.4 lb/ft 1 Btu =252 Cal 1 Btu = 778 ft.lbf 1 hp = 550 ft.lbf/sec
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Dimensional Analysis
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY