Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Q15.
![### Calculation of Mass from Volume and Density
**Given:**
- Volume (\( V \)) of liquid = 255 mL
- Density (\( d \)) of liquid = 0.880 g/mL
**Objective:**
- Calculate the mass (\( m \)) of the liquid.
**Formula:**
\[ \text{Density} (d) = \frac{\text{Mass} (m)}{\text{Volume} (V)} \]
**Rearranging the formula to solve for mass (\( m \)):**
\[ m = d \times V \]
**Substituting the given values:**
\[ m = 0.880 \, \text{g/mL} \times 255 \, \text{mL} \]
**Step-by-step Calculation:**
\[ m = 0.880 \times 255 \]
\[ m = 224.4 \, \text{g} \] *(It seems there's an error in the final handwritten result, as the multiplication is done incorrectly)*
**Final Mass:**
\[ m = \boxed{224.4 \, \text{g}} \]
### Detailed Explanation of Calculation
The calculation above aims to find the mass of a liquid when given its volume and density. The formula for density is manipulated to directly solve for mass. By substituting the volume (255 mL) and density (0.880 g/mL) into the formula, we get the mass. The handwritten result of 198g may be due to incorrect multiplication. The correct calculation should yield a mass of 224.4g.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F538f3e83-7f0d-4c1a-a688-bdf41958b228%2F9e779419-59a6-479d-b1de-7637ed2dbcb6%2Fp2ctyhv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Calculation of Mass from Volume and Density
**Given:**
- Volume (\( V \)) of liquid = 255 mL
- Density (\( d \)) of liquid = 0.880 g/mL
**Objective:**
- Calculate the mass (\( m \)) of the liquid.
**Formula:**
\[ \text{Density} (d) = \frac{\text{Mass} (m)}{\text{Volume} (V)} \]
**Rearranging the formula to solve for mass (\( m \)):**
\[ m = d \times V \]
**Substituting the given values:**
\[ m = 0.880 \, \text{g/mL} \times 255 \, \text{mL} \]
**Step-by-step Calculation:**
\[ m = 0.880 \times 255 \]
\[ m = 224.4 \, \text{g} \] *(It seems there's an error in the final handwritten result, as the multiplication is done incorrectly)*
**Final Mass:**
\[ m = \boxed{224.4 \, \text{g}} \]
### Detailed Explanation of Calculation
The calculation above aims to find the mass of a liquid when given its volume and density. The formula for density is manipulated to directly solve for mass. By substituting the volume (255 mL) and density (0.880 g/mL) into the formula, we get the mass. The handwritten result of 198g may be due to incorrect multiplication. The correct calculation should yield a mass of 224.4g.

Transcribed Image Text:### Educational Website Transcription
#### Physics and Measurements: Multiple Choice Questions
---
**Q13. Convert 27 m/s to km/hr.**
(a) 97 km/hr
(b) 7.5 km/hr
(c) 1.6 km/hr
(d) 0.027 km/hr
**Q14. A cube measures 2.5 cm on each edge and has a mass of 66.9 g. Calculate the density of the material that composes the cube. (The volume of a cube is equal to the edge length cubed.)**
(a) 10.7 g/cm³
(b) 4.3 g/cm³
(c) 0.234 g/cm³
(d) 26.7 g/cm³
**Q15. What is the mass of 225 mL of a liquid that has a density of 0.880 g/mL?**
(a) 198 g
(b) 0.0039 g
(c) 0.198 g
(d) 0.256 g
**Q16. What is the edge length of a 155-g iron cube? (The density of iron is 7.86 g/cm³, and the volume of a cube is equal to the edge length cubed.)**
(a) 0.0197 cm
(b) 19.7 cm
(c) 1218 cm
(d) 2.70 cm
---
#### Relevance
Measurement is a hallmark of science, and you must communicate the precision of a measurement so that others know how reliable the measurement is. When you write or manipulate measured quantities, you must show and retain the precision with which the original measurement was made.
---
##### Answers:
1. (b)
2. (d)
3. (c)
4. (a)
5. (c)
6. (d)
7. (a)
8. (c)
9. (b)
10. (d)
11. (b)
12. (d)
13. (a)
14. (b)
15. (a)
16. (d)
Note: The transcription above includes the text from the image along with the multiple choices for each question and the section on relevance. There are no graphs or diagrams accompanying these questions.
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