Q10:- Gasoline (p =50 lbm ft) is to be siphoned from a tank. The friction loss in the line is F =0.80 ft.lbr Abm. Estimate how long it will take in minute to siphon 5.00 gal, neglecting the change in liquid level in the gasoline tank during this process and assuming that both point 1 and 2 at latm,take the velocity in point 1= zero .Given that g=32.17 ft/sec', ge=32.17 Ibm.ft/lbf.sec', ft=12 in, 1ft= 7.48 gal -in. 12 hose 2.5 ft

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Q10: Gasoline (p =50 lbm ft) is to be siphoned from a tank. The friction loss in the line is
F =0.80 ft.lbr Abm. Estimate how long it will take in minute to siphon 5.00 gal, neglecting the
change in liquid level in the gasoline tank during this process and assuming that both point
1 and 2 at latm,take the velocity in point 1= zero .Given that g=32.17 ft/sec', ge=32.17
Ibm.ft/Ibf.sec', ft=12 in, 1ft'= 7.48 gal
-in. 10 hose
1.
2.5 ft
Transcribed Image Text:Q10: Gasoline (p =50 lbm ft) is to be siphoned from a tank. The friction loss in the line is F =0.80 ft.lbr Abm. Estimate how long it will take in minute to siphon 5.00 gal, neglecting the change in liquid level in the gasoline tank during this process and assuming that both point 1 and 2 at latm,take the velocity in point 1= zero .Given that g=32.17 ft/sec', ge=32.17 Ibm.ft/Ibf.sec', ft=12 in, 1ft'= 7.48 gal -in. 10 hose 1. 2.5 ft
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