Q1.An object with negative charge is placed in a region of space where the electric field is directed vertically upward. What is the direction of the electric force exerted on this charge? (a) It is up. (b) It is down. (c) There is no force. (d) The force can be in any direction.
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Q: Suppose you have an electric field that exerts a 1.85 × 10-5 N upward force on a -1.95 μC charge.…
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Q: charge, q = 3 x 10° C is 30 cm form a small dipole along it agnitude of the force on the charge is 5…
A: Solution
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Q: Consider a positive charge qq located at (−d,0)(−d,0), and a negative charge −q−q located at…
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Q: A very long wire placed along the y-axis has a line charge density λ = 90 µC/m. A) Calculate the…
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Q: 1. Three point charges are located at the vertices of an equilateral triangle of side length 1 = 10…
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Q: An electron has an initial velocity of 5.00 x 106 m/s in a uniform 2.00 x 105 N/C strength electric…
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Q: 8. Three point-like charges are placed at the corners of an equilateral triangle as shown in the…
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Q: A +6 nC charge is located 2.5 meters to the right of a +4 nC charge. Determine the magnitude of the…
A: first charge (q1) = 4 nCSecond charge (q2) = 6 nC distance between the two charges (d) = 2.5 m Let…
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- How can the presence, magnitude, and direction of a non-zero electric field be determined? a. Place a neutral particle in the region containing the field. If it remains at rest, there is a non-zero electric field. b. Place a neutral particle in the region containing the field. It will accelerate in the direction of the electric field. The magnitude of the acceleration can be used to determine the field. c. Place a positively charged particle in the region containing the field. If it remains at rest, there is a non-zero electric field. d. Place a positively charged particle in the region containing the fi eld. It will accelerate in the direction of the electric fi eld. The magnitude of the acceleration can be used to determine the field.a) A particle with a mass of 0.003 grams and a charge of-5x10°C was placed in an upward electric field with a magnitude of 350,000 N/C. What is the direction of the acceleration that the particle will feel? 22 b) What is the magnitude of the acceleration that the particle will feel? b) If it is in the field for 0.25 seconds, how far will it go?10. Three point-like charges are placed at the corners of an equilateral triangle as shown in the figure. Each side of the triangle has a length of 20.0 cm, and the point (C) is located half way between qı and q3 along the side. Find the magnitude of the electric field at point (C). Let q1 = -1.60 µC, q2 = +2.60 µC, and q3 = +5.20 µC. N/C oof19 00 q3 19.0of19.0of19.oof19 oof19.of of19 0of19 0of19 0of19.oof19 oof of19 0of19 oof19 0
- Q5: Two 2µC point charges are located on the x axis. One is at x=1m, and the other is at x=-1m. (a) Determine the electric field on the y-axis at y= 0.5m. (b) Calculate the electric force on a -3µC charge placed on the y-axis at y=0.5m.Question 4. Three equal positive charges are at the corners of an equilateral triangle of side a as in Figure 4. Assume the three charges together create an electric field. a) Sketch the electric field lines in the plane of the charges. b) Find the location of one point (other than infinity) where the electric field is zero. c) What are the magnitude and the direction of the electric field at P due to the two charges at the base? Figure 4:2. Suppose that charge #1 is positioned at the origin (x = 0 m, y = 0 m) and has a magnitude of +2.6 μC, and that charge #2 is positioned on the y-axis at y = 0.16 m and has a magnitude of -4.3 µC. Find the x- and y-components of the electric field on the x-axis at x = 0.21 m. Also, find the x- and y-components of the force on a charge of +6.3 nC placed at this point (x = 0.21 m).