Q1. Two signals x(t) and h(t) are given by x(t) =8(t – 1) + 8(t+ 1) + 8 (t – ;) + 8 (t+;) and h(t) = e-2tu(t) (a) Find the Fouier transform of both signals, x(t) and h(t), using definition.

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Q1.
Two signals x(t) and h(t) are given by
x(t) =8(t – 1) + 8(t+ 1) + 8 (t – ;) + 8 (t +;) and h(t) = e-2'u(t)
(a)
Find the Fouier transform of both signals, x(t) and h(t), using definition.
(b)
Find the Fouier transform of both signals, x(t) and h(t), using table.
(Write down which property and pair you're using, and the result of applying the
table as steps)
(c)
Compute y(t) where y(t) is the convolution of these two signals, that is,
y(t) = x(t) * h(t).
(d)
Determine the Fourier Transform of y(t) using Table. Verify that it is equal
to the product of the individual transforms of x(t) and h(t): Y(w) = X(w) ·
H(w)
Transcribed Image Text:Q1. Two signals x(t) and h(t) are given by x(t) =8(t – 1) + 8(t+ 1) + 8 (t – ;) + 8 (t +;) and h(t) = e-2'u(t) (a) Find the Fouier transform of both signals, x(t) and h(t), using definition. (b) Find the Fouier transform of both signals, x(t) and h(t), using table. (Write down which property and pair you're using, and the result of applying the table as steps) (c) Compute y(t) where y(t) is the convolution of these two signals, that is, y(t) = x(t) * h(t). (d) Determine the Fourier Transform of y(t) using Table. Verify that it is equal to the product of the individual transforms of x(t) and h(t): Y(w) = X(w) · H(w)
FT pairs
Fourier Transform Table
x(t)
X ()
X(@)
6 (t)
1
1
1
6 (f)
216(a)
eriat,
2n8 (a – @o)
6(t - to)
e/ 2
6 (f - 6)
-
cos(2rfot)
*[8 (a - ao) + 6(a +ap)]
sin(27ot)
- ja[8 (a - an) - 6 (a +an)]
rect(t)
sinc(f)
sinc
sinc(t)
rect(f)
rect
2я
A (t)
sinc (
sinc
27
sinc ()
A(f)
e-at u(t), a> 0
a +j2af
a+ ja
te aut), a> 0
1
1
(a+ ja)?
a>0
2a
2a.
(a²+(2xf)?
(a? + (@)?
e-
e-ar
sgn(t)
1
2
jnf
ja
ut)
1
T8 (a) +.
ja
j2af
ja
6(t)
dt
00
1
E 6(t - nTo)
-
To
To
To
7--00
7--00
Transcribed Image Text:FT pairs Fourier Transform Table x(t) X () X(@) 6 (t) 1 1 1 6 (f) 216(a) eriat, 2n8 (a – @o) 6(t - to) e/ 2 6 (f - 6) - cos(2rfot) *[8 (a - ao) + 6(a +ap)] sin(27ot) - ja[8 (a - an) - 6 (a +an)] rect(t) sinc(f) sinc sinc(t) rect(f) rect 2я A (t) sinc ( sinc 27 sinc () A(f) e-at u(t), a> 0 a +j2af a+ ja te aut), a> 0 1 1 (a+ ja)? a>0 2a 2a. (a²+(2xf)? (a? + (@)? e- e-ar sgn(t) 1 2 jnf ja ut) 1 T8 (a) +. ja j2af ja 6(t) dt 00 1 E 6(t - nTo) - To To To 7--00 7--00
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