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Q1. Part a. Identify Ordinary Differential Equations (ODEs) and write the ODEs in the form of F(t, x,x) = 0, or F(t, x, x, x) = 0, or F(t, y, y) = 0, or F(t, y, y, ÿ) = 0, or F(x, y, y) = 0, or F(x, y, y, ÿ) = 0, or F(z, p, p,p) = 0. a. b. c. d. e. (1-3x)ÿ - 2xy + 6y = 5x²+2x² + 2 = 0. d²y dx² +7²x = 27 where 7 is a constant. Pu(X1, X2, X3) dx² (sin ß). dy (cos 3) = 3 where ß is a scalar parameter. dx d²x dt² J²u(x1, x2, x3) Əx² sin x. + dx dt + d²x f. 2M +30 +2Kx(t) = f(t). dt² J²u(x1, x2, x3) dx² = 0.

Q1. Part a. Identify Ordinary Differential Equations (ODEs) and write the ODEs in the form of F(t, x,x) = 0, or F(t, x, x, x) = 0, or F(t, y, y) = 0, or F(t, y, y, ÿ) = 0, or F(x, y, y) = 0, or F(x, y, y, ÿ) = 0, or F(z, p, p,p) = 0. a. b. c. d. e. (1-3x)ÿ - 2xy + 6y = 5x²+2x² + 2 = 0. d²y dx² +7²x = 27 where 7 is a constant. Pu(X1, X2, X3) dx² (sin ß). dy (cos 3) = 3 where ß is a scalar parameter. dx d²x dt² J²u(x1, x2, x3) Əx² sin x. + dx dt + d²x f. 2M +30 +2Kx(t) = f(t). dt² J²u(x1, x2, x3) dx² = 0.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Q1. Part a. Identify Ordinary Differential Equations (ODEs) and write the ODEs in the form of F(t, x, x) = 0, or F(t, x, x, x) = 0, or F(t, y, y) = 0, or F(t, y, ÿ, ÿ) = 0, or F(x, y, y) = 0, or F(x, y, y, ÿ) = 0, or F(z, p,p, p) = 0. a. b. 5x + 2x² + 2 = 0. C. d. (1 − 3x)ÿ - 2xy + 6y = sin x. e. (sin 3) d²y dx² dy - (cos 3). = 3 where ß is a scalar parameter. dx d²x dt² J²u(x1, x2, X3) dx² + T²x = 2T where is a constant. + dx dt P²u(x1, x2, x3) ²u(x1, x2, x3) dx² əx² + d²x f. 2M +3C +2Kx(t) = f(t). dt² = 0.
Transcribed Image Text:Q1. Part a. Identify Ordinary Differential Equations (ODEs) and write the ODEs in the form of F(t, x, x) = 0, or F(t, x, x, x) = 0, or F(t, y, y) = 0, or F(t, y, ÿ, ÿ) = 0, or F(x, y, y) = 0, or F(x, y, y, ÿ) = 0, or F(z, p,p, p) = 0. a. b. 5x + 2x² + 2 = 0. C. d. (1 − 3x)ÿ - 2xy + 6y = sin x. e. (sin 3) d²y dx² dy - (cos 3). = 3 where ß is a scalar parameter. dx d²x dt² J²u(x1, x2, X3) dx² + T²x = 2T where is a constant. + dx dt P²u(x1, x2, x3) ²u(x1, x2, x3) dx² əx² + d²x f. 2M +3C +2Kx(t) = f(t). dt² = 0.
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