Q1/. Determine the range of mass m, for which the system is in equilibrium. The coefficient of static friction between the block and the incline is 4, = 0.25. Neglect friction associated with the pulley. See figure (1).
Q1/. Determine the range of mass m, for which the system is in equilibrium. The coefficient of static friction between the block and the incline is 4, = 0.25. Neglect friction associated with the pulley. See figure (1).
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
Transcribed Image Text:Homework
Q1/. Determine the range of mass m, for which the system is in equilibrium. The coefficient of static friction between the block and
the incline is 4, = 0.25. Neglect friction associated with the pulley. See figure (1).
Q2/. The automobile has a mass of 1 Mg and center of mass at G. Determine the towing force F required to move the car if the back
brakes are locked, and the front wheels are free to roll. Take us = 0.25. See figure (2).
Q3/. Determine the maximum force P that can be applied without causing movement of the 200 lb crate that has a center of gravity at
G. The coefficient of static friction at the floor is 4, = 0.4. See figure (3).
1.5 ft 1.5 ft
2.5 ft
G.
06m
4.5 ft
03 m
20
3.5 f
+Im1.50 m-
0.75 m
Fig (1)
Fig (2)
Fig (3)
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