Q1. B. In the single-phase half-wave rectifier shown below, assume that the load current iola is constant (load inductance L is very large). (i) Sketch the load voltage waveform vo for a = 90° and find its average value V dc. 10 2 find the average and rms values of the (ii) For R = diode current ia for a = 45°. V₁ (240 V rms) + Vo L (large)

Q1. B. In the single-phase half-wave rectifier shown below, assume that the load current iola is constant (load inductance L is very large). (i) Sketch the load voltage waveform vo for a = 90° and find its average value V dc. 10 2 find the average and rms values of the (ii) For R = diode current ia for a = 45°. V₁ (240 V rms) + Vo L (large)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Assuming an ideal diode, sketch Vị, Va and ia for the half-wave rectifier below. The input is sinusoidal waveform with a frequency of 60 Hz. Also, determine and sketch V, and i, Ideal -2 V 2.2 ka 6.8 k
Topic. Rectifiers.
Create a Half-Wave Rectifier circuit. Use a resistor of 1000 Ohms. Input Voltage should be 95VAC - 65Hz Plot both the Input voltage and output voltage. Determine the Voltage drop across the diode by subtracting the output voltage to the input voltage peaks. Create a Bridge-Type Full Wave Rectifier Circuit. Repeat the steps done on the Half-Wave Rectifier circuit.
5. Assuming an ideal diode, sketch V, V. and ig for the half-wave rectifier below. The input is sinusoidal waveform with a frequency of 60 Hz. Also, determine and sketch V. and i, Ideal -2V 2.2 ka 6.8 k2
P) For single - phase half-controlled bridge rectifier shown in the figure: 1. Derive a formula for mean load Voltage. 2. Draw the waveforms of Ve,is,iz, i3, iy and io assuming highly inductive Load and =45. T. T3 Dy
In the single-phase half-wave diode rectifier with an inductive load, if the inductor starts discharging its energy and continuous until 205 degrees, the value of inversion conduction-angle of a diode is:
Given the half-wave rectifier circuit shown 220V 60Hz 220V:Es Es D RL The load resistor is 2292 and it dissipates 2W. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average diode current and PIV of the diode.
The four diodes used in a bridge rectifier circuit have forward resistances which may be considered constant at 1 ohm and infinite reverse resistance. The alternating supply voltage is 220 V r.m.s. and load resistance is 580 ohm. Calculate (i) mean load current and (ii) power dissipated in each diode.
5. Assuming an ideal diode, sketch Vị, Va and ia for the half-wave rectifier below. The input is sinusoidal waveform with a frequency of 60 Hz. Also, determine and sketch V, and i, Ideal V-2 V 2.2 ka R26.8 ka
a. Determine V. and the required PIV rating of each diode for the configuration shown. b. Calculate the average voltage, RMS load voltage, and efficiency of the rectifier network. c. Sketch the V. 100 V Ideal diodes -100 V 2.2 ka
Answer a,b,c,d
The input to a 3-phase full-wave rectifier is 60 Hz AC voltage. If the voltage drop across diodes is 0 V, The RMS voltage at the load would be: O A. None of the other choices are correct O B. Cannot tell until we have more information O C. Lower than the RMS voltage at the input O D. Higher than the RMS voltage at the input O E. The same as the RMS voltage at the input