Q1. (a) What are the electric field magnitude and polarisation direction of the following plane electromagnetic waves: i) Ex = cos(wt - kz), Ey = √3 cos(wt - kz), E₂ = 0; ii) Ex = cos(wt - kz), Ey = √√3 cos(wt - kz + π), E₂ = 0; iii) Ex = 2 cos(wt - kz), Ey = 2sin(wt - kz), Ez = 0.

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(Photonics) please provide the working to the question in the image, thank you!
Q1.
(a)
What are the electric field magnitude and polarisation direction
of the following plane electromagnetic waves:
i) Ex = cos(wt - kz), Ey = √√3 cos(wt – kz), E₂ = 0;
ii) Ex = cos(wt - kz), Ey = √√3 cos(wt − kz + n), E₂ = 0;
iii) Ex = 2 cos(wt - kz), Ey=2sin(wt - kz), Ez = 0.
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Transcribed Image Text:Q1. (a) What are the electric field magnitude and polarisation direction of the following plane electromagnetic waves: i) Ex = cos(wt - kz), Ey = √√3 cos(wt – kz), E₂ = 0; ii) Ex = cos(wt - kz), Ey = √√3 cos(wt − kz + n), E₂ = 0; iii) Ex = 2 cos(wt - kz), Ey=2sin(wt - kz), Ez = 0. -
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