* Q1 X1 +x2] 3 X1 4 X2 If 3 [x3 X4] [x3 + X4 1. x1 = -2, x2 = 2, x3 = -2, x4 = -3. 2. x1 = 2, x2 =-2, x3 = -2, x4 = -3 3. x1 = 2, x2 = 2, x3 = 2, x4 =-3 4. x1 2, x2 = 2, x3 = -2, x4 = 3 5. x1 = 2, x2 = 2, x3 = -2, x4 = -3 %3D %3D %3D 1 0 2 O 3 O 4 O 5 O

Q: In Exercises 7.2.1-7.2.8 find the power series in a for the general solution. 1. (1+x²)y" + 6xy'…

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Q: x+6 x+5 + = 8 2 3.

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Q: then If A(-3-20) = Au = -2 ---A 2 and Av= -1 3 2

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A:

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A:

Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.