Q1: write a program to find the :value of y bläi 5 (x2-z2 if (x and z >0) x3 Y = {1 if (x = 0 and z = 0) %3D 3z^2 if (x and z < 0) Vx2+1 إجابتك
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- Greatest Common Divisor Two integers A and B have the greatest common divisor which is the largest positive integer that divides A and B, evenly, without a remainder. One way to find the Greatest Common Divisor is to consider the prime factors for A = 372 and B = 84 as shown below. 372 223 * 31 84 22*3*7 GCD (372,84) = 2²*3= 12 In a well-documented Python program, hmwk3Q3.py, query the user for two integers. Use a while-loop to find the remainder R when dividing A by B.Replace the value of A with the value of B and replace the value of B with the value of R.Continue this process within the while-loop until the value of B is zero. At that time the value of A will be the GCD. In a comment, provide the response to your program when A= 98,025,733,547 and B = 2,345,109,894,323.Caesars Cypher in C programming language How do you program an encryption and decryption for a Caesars Cypher that covers all the possible ASCII characters? In this there should be a shift over K = 5 but the example below is K = 3. This should result in actual character and not the control ASCII represenations. For example: >>> $ encrypt(I have a key)N%mf{j%f%pj~>>> $ encrypt(see me at 3)xjj%rj%fy%8>>> $ decrpyt(|jfw%ns%gqzj)wear in blue Assume that the text parsing method has been succesful and it's the encryption/decryption of the char array that needs to be factored. Formula Encryption -> C = E(k, P) = (P + k) (mod 26) Decryption -> P = D(k, C) = (C - k) (mod 26) Where k = 5Python def fancy_quadratic(a: float, b: float, c: float, x: float) -> float: """ fancy_quadratic(a, b, c, x) returns a * x^2 + b*x + c # TODO: replace this TODO with examples of fancy_quadratic() :param a: coefficient a :param b: coefficient b :param c: coefficient c :param x: operand float value :returns: result of the operation """ pass # TODO: replace 'pass' with the function implementation # TODO: replace this line with the function signature described by the purpose: """ negate_a_mul_b(a, b) returns value of the operation -a * b example: negate_a_mul_b(-2.0, 1.0) -> 2.0 example: negate_a_mul_b(-2.0, -2.0) -> -4.0 example: negate_a_mul_b(1.0, -2.0) -> 2.0 example: negate_a_mul_b(0.0, 0.0) -> 0.0 TODO: add param and return descriptions here """ pass # TODO: replace 'pass' with the function implementation
- C++ I am lost, can you help me find my way please Finding values in vectors. Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 2, 1, 2} and matchValue is 2 , then numMatches should be 3.Your code will be tested with the following values:* matchValue: 2, userValues: {2, 2, 1, 2} (as in the example program above)* matchValue: 0, userValues: {0, 0, 0, 0}* matchValue: 50, userValues: {10, 20, 30, 40} #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; int matchValue; unsigned int i; int numMatches = -99; // Assign numMatches with 0 before your for loop vector<int> userValues(NUM_VALS); cin >> matchValue; for (i = 0; i < userValues.size(); ++i) { cin >> userValues.at(i); } cin >> numMatches; numMatches = userVals.at(0); for (i = 0; i < userVals.size(); ++i) { if…Q/lf 2 = a, 7 = b, 2 = c, and 10 = d are integer variables, then the next print run is It (a>=b || a==c) a=b; if (a>c || (a+c)>d) d=c; if (ddef square(x): return x * X def halve(x): return x // 2 def twice(f,x): """Apply f to the result of applying f to x >>> twice (square,3) 81 >>> twice (square, 4) 256 >>> twice (halve, 32) 8 >>> twice (halve, 80) 20 *** YOUR CODE HERE ***"in C++ use this function to calcul the range: function range step Specified value of y y = 0.05*x3+6sin(3x)+4 From -2.5 to 2.5 0.5 -2 The program will calculate average value of y for the given range. To find the average, usestd::accumulate using algorithm header and divide by the number of elements. The output must be write with the result:Average value of function y for the given range is : ;]: Write a piece of code that calculates the uncertainty SP from the error propagation rule for sums, SP = 2√√√(SL)² + (SW)² A few hints: Again, you're translating the above equation into code. • Your result should be stored in a variable uncertainty_P_errorprop • For the square root function, use np. sqrt() • For squares, use ** #YOUR CODE HERE raise Not ImplementedError() ]: ▼ # Print the uncertainty print ("uncertainty of circumference P from error propagation: 11 , uncertainty_P_errorprop)See the sample outputs for more clarification. Project Specifications Input for this project: Values of the grid (row by row) Output for this project: Whether or not the grid is magic square Programmer's full name Project number Project due date Processing Requirements Use the following template to start your project: #include using namespace std; // Global constants // The number of rows in the array // The number of columns in the array // The value of the smallest number // The value of the largest number const int ROWS = 3; const int COLS = 3; const int MIN = 1; const int MAX = 9; // Function prototypes bool isMagicsquare(int arrayRow1[], int arrayRow2 [], int arrayRow3[], int size); bool checkRange (int arrayRow1[], int arrayRow2[], int arrayRow3[], int size, int min, int max); bool checkUnique(int arrayRow1[], int arrayRow2[], int arrayRow3[], int size); bool checkRowSum (int arrayrow1[], int arrayrow2[], int arrayrow3[], int size); bool checkColiSum(int arrayrow1[], int…% n = input('Please enter the value of num: \n'); a = randi([1, 3]); b = randi([-4, 0]); c = 4; d = randi([4, 100]); % or -randi([5, 100]) funcif(a) funcif(b) funcif(c) funcif(d) global w x y z function funcif(num) if %%% disp(%%%) z = %%% else if %%% if %%% disp(%%%) w = %%% else disp(%%%) x = %%% end else disp(%%%) y = %%% end end end2- The factorial n! of a positive integer n is defined as n! = 1*2*3 . .. * (n-1) * n Where 0! = 1 Write a function to calculate the factorial of a number. Argument: A number n of type unsigned int. Returns: The factorial n! of type long double. Write two versions of the function, where the factorial is • calculated using a loop calculated recursively Test both functions by outputting the factorials of the numbers 0 to 20.Let E = {a} and L = E*. Which of the following belongs to 24? %3D O a. À O b. (A) Oc. Ø d. (0)