Q1/ The work done on an object is equal to the integral of the force on that object dotted with its displacent. This looks like W=[(F.ds) (W is work, F is force, and ds is the infinitesimally small displacement vector). For a force whose direction is the line of motion, the equation becomes W=[(Fdx). If the force on an object as a function of displacement is F(x)=3x2+x, what is the work as a function of displacement (using calculus application) W(x)? Assume W(0)=0 and the force is in the direction of the object's motion.

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Q1/ The work done on an object is equal to the integral of the force on that object dotted with its
displacent.
This looks like W=[(F.ds) (W is work, F is force, and ds is the infinitesimally small
displacement vector). For a force whose direction is the line of motion, the equation
becomes W=[(Fdx).
If the force on an object as a function of displacement is F(x)=3x2+x, what is the work as a
function of displacement (using calculus application) W(x)? Assume W(0)=0 and the force
is in the direction of the object's motion.
Transcribed Image Text:Q1/ The work done on an object is equal to the integral of the force on that object dotted with its displacent. This looks like W=[(F.ds) (W is work, F is force, and ds is the infinitesimally small displacement vector). For a force whose direction is the line of motion, the equation becomes W=[(Fdx). If the force on an object as a function of displacement is F(x)=3x2+x, what is the work as a function of displacement (using calculus application) W(x)? Assume W(0)=0 and the force is in the direction of the object's motion.
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