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Q1/ The uniform ladder is 2-m long and makes an angle of = 60° with the floor. If the wall at B is smooth and the coefficient of static friction at A is PA = 0.3, determine if the ladder can remain in the position shown. NB B 1 m B (2 m)(sin 60°) = 1.732 m 1 m Mass of ladder = 10 kg Weight = mg = (10 kg)(9.81 m/s) = 98.1 N | 60° fA A |NA (1 m)(cos 60°) = 0.5 m-

Q1/ The uniform ladder is 2-m long and makes an angle of = 60° with the floor. If the wall at B is smooth and the coefficient of static friction at A is PA = 0.3, determine if the ladder can remain in the position shown. NB B 1 m B (2 m)(sin 60°) = 1.732 m 1 m Mass of ladder = 10 kg Weight = mg = (10 kg)(9.81 m/s) = 98.1 N | 60° fA A |NA (1 m)(cos 60°) = 0.5 m-

Principles of Foundation Engineering (MindTap Course List)
Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN:9781305081550
Author:Braja M. Das
Publisher:Braja M. Das
Chapter6: Vertical Stress Increase In Soil
Section: Chapter Questions
Problem 6.4P: Refer to Figure P6.4. A strip load of q = 900 lb/ft2 is applied over a width B = 36 ft. Determine...
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Q1/ The uniform ladder is 2-m long and makes an angle of = 60° with the floor. If the wall at B is smooth and the coefficient of static friction at A is µA = 0.3, determine if the ladder can remain in the position shown. NB B 1 m Mass of ladder = 10 kg (2 m)(sin 60°) = 1.732 m 1 m Weight = mg = (10 kg)(9.81 m/s²) = 98.1 N 60° fa (1 m)(cos 60°) = 0.5 m
Transcribed Image Text:Q1/ The uniform ladder is 2-m long and makes an angle of = 60° with the floor. If the wall at B is smooth and the coefficient of static friction at A is µA = 0.3, determine if the ladder can remain in the position shown. NB B 1 m Mass of ladder = 10 kg (2 m)(sin 60°) = 1.732 m 1 m Weight = mg = (10 kg)(9.81 m/s²) = 98.1 N 60° fa (1 m)(cos 60°) = 0.5 m
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