Q1) The RTL gate has:k = 0.95 VCE (sat) = 0.2V, VBE (FA) = 0.6V,VBE (sat) = 0.8V and BF = 150.VCC5V%3DRC {IKSolution%3DFor RTL find :-RBVOUT1. The logic gate of RTL circuit is2. VOL is equal3. VIL is equalQo1VIN100KRBQo24. VIH is equal100K5. At VIN = 0.61 volt, the state of transistorsQo1 and Qo2 respectively are6. At fan-out = 5 the power dissipation (avg.) is equal7. At VOH(min) = 3.5volt, Fan out max is equal%3D

Note: As per our policy, I have attempted the first three subparts. Given data: VCE(sat)=0.2 V…

Q1) The RTL gate has: k = 0.95 VCE (sat) = 0.2V, VBE (FA) = 0.6V, VBE (sat) = 0.8V and BF = 150. VCC 5V %3D Solution RC 3 1K %3D For RTL find :- RB VOUT 1. The logic gate of RTL circuit is 2. VOL is equal VIN Qo1 100K 3. VIL is equal 4. VIH is equal RB w- Qo2 100K 5. At VIN = 0.61 volt, the state of transistors Qo1 and Qo2 respectively are 6. At fan-out 5 the power dissipation (avg.) is equal

Q1) The RTL gate has: k = 0.95 VCE (sat) = 0.2V, VBE (FA) = 0.6V, VBE (sat) = 0.8V and BF = 150. VCC 5V %3D Solution RC 3 1K %3D For RTL find :- RB VOUT 1. The logic gate of RTL circuit is 2. VOL is equal VIN Qo1 100K 3. VIL is equal 4. VIH is equal RB w- Qo2 100K 5. At VIN = 0.61 volt, the state of transistors Qo1 and Qo2 respectively are 6. At fan-out 5 the power dissipation (avg.) is equal

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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