Q1- The following data was obtained tensile test on a specimen of 10 mm diameter and gauge length Lo-50 mm: load(KN) elongation(mm) | 92.7 149 0 38 0 0.02 160.4 155 2.03 3.55 4.06 5.1 5.84 76.2 107 142 124.7 0.12 0.25 0.50 Using the graphic paper supplied, Plot engineering stress-strain curves, then determine the (ay , ey), (ou, eu), (of., ef), modulus of elasticity, then detected in the draw ((strain hardening (n)), (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region)}?

Q1- The following data was obtained tensile test on a specimen of 10 mm diameter and gauge length Lo-50 mm: load(KN) elongation(mm) | 92.7 149 0 38 0 0.02 160.4 155 2.03 3.55 4.06 5.1 5.84 76.2 107 142 124.7 0.12 0.25 0.50 Using the graphic paper supplied, Plot engineering stress-strain curves, then determine the (ay , ey), (ou, eu), (of., ef), modulus of elasticity, then detected in the draw ((strain hardening (n)), (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region)}?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Problem 1.1MA

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Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

Q1- The following data was obtained tensile test ɔn a specimen of 10 mm diameter and gauge
length Lo=50 mm:
0 38
| 76.2 92.7 107 149 160.4 | 155 142 124.7
load(KN)
| elongation(mm) 0 0.02 0.12 0.25 0.50 2.03 3.55 4.06 5.1 5.84
Using the graphic paper supplied, Plot engineering stress-strain curves, then determine the
(ay, ey), (ou , eu), (of,, ef), modulus of elasticity, then detected in the draw ((stroin hardening
(m)), (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic)
region))?

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Problem :- The following data was obtained tensile test on a specimen of 6 mm diameter and gauge length Lo=30 mm: load(KN) 0 40 80 95 90 135 150.2 145 130 120 elongation(mm) 0 0.022 0.13 0.25 0.55 2.01 3.88 4.12 5.22 6 Plot engineering and True (stress-strain) curves, then determine the (oy, ɛy), (ou, ɛu), (of, , ef), ductility, modulus of elasticity. Then select on the drawing ((strain hardening (n)) , (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region)?
1 - A tensile test is carried out on a specimen of mild steel of gauge length 40 mm and diameter 7.42 mm. The results are: Load (kN) 10 17 25 30 34 37.5 38.5 36 Extension (mm) 0 0.05 0.08 0.11 0.14 0.20 0.40 0.60 0.90 At fracture the final length of the specimen is 40.90 mm. Plot the load/ extension graph and determine (a) The modulus of elasticity for mild steel, (b) The yield stress, (c) The ultimate tensile strength, (d) The percentage elongation 2 - An aluminum alloy specimen of gauge length 75 mm and of diameter 11.28 mm was subjected to a tensile test, with these results: Load (kN) 2.0 6.5 11.5 13.6 16.0 18.0 19.0 20.5 19.0 Extension (mm) 0 0.012 0.039 0.069 0.080 0.107 0.133 0.158 0.225 0.310 The specimen fractured at a load of 19.0 kN. Determine (a) the modulus of elasticity of the alloy, (b) The percentage elongation. (c) The ductility in term of reduction of area (d) Fracture stress (e) Tensile strength
The following data was obtained tensile test on a specimen of 6 mm diameter and gauge length Lo=30 mm: 142 124.7 5.1 5.84 Using the graphic paper supplied, Plot engineering stress-strain curves, then determine the 0| 38 160.4 155 4.06 3.55 76.2 load(KN) elongation(mm) 00.02 92.7 107 149 0.12 0.25 0.50 |2.03 (gy sy), (gu, eu), (of, sf), modulus of elasticity, then detected in the draw ((strain hardening (n)), (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region))?
Solve the problem
In a tensile test of stainless steel, the following data were obtained: Load (N) 7,200 11,250 13.500 16,200 18.900 Elongation (mm) 0.0 0.505 2.03 5.08 20,200 15.24 20,700 13,200 24.90 10.16 21.80 The dimensions of the cylindrical specimen were initial length L₁ = 50.8 mm and initial arca A₁ - 35.8 mm² and the area at fracture was Ar 10.0 mm². Plot the stress-strain diagram and determine the following: a) Modulus of elasticity b) The yield strength at a strain offset of 0.002 c) Ultimate strength d) Fracture strength
I need the answer as soon as possible
I want answers to all four questions if possible. Thanks for help :) Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Calculate the fracture strength (in MPa) of the material. - Calculate the percent elongation of the specimen at fracture point. - Determine the modulus of resilience (in N.mm/mm3) of the material. (Use at least five decimal units) - Determine the toughness index number (in N.mm/mm3) of the material.
A tension test was performed on a specimen having an original diameter of 13.0 mm and a gauge length of 50 mm. Load (kN) Elongation (mm) 0 11.1 31.9 37.8 40.9 43.6 53.4 62.3 64.5 62.3 58.8 0 0.0175 0.0600 0.1020 0.1650 0.2490 1.0160 3.0480 6.3500 8.8900 11.9380 Using the data listed in the table, plot the stress-strain diagram. Use a scale of 20 mm = 50 MPa and 20 mm = 0.05 mm/mm. Part A From the diagram, determine approximately the modulus of toughness. Express your answer to three significant figures and include the appropriate units. U = Submit O μA Value Request Answer Units < Return to Assignment Provide Feedback ?
σ (ksi) 105 90 75 60 45 30 15 0 8 0 0 0.20 0.25 0.30 0.35 0.05 0.10 0.15 0.001 0.002 0.003 0.004 0.005 0.006 0.007 € (in./in.) The stress-strain diagram from tensile test data for a metal alloy is shown. If the diameter of testing sample is 0.5 in determine: a) UTS b) Yield Strength c) Braking/ Failure Strength d) Young Module of Elasticity e) The load causing yielding in material
Load (N) Elongation (mm) In a tensile test of stainless steel, the following data were obtained: 7,200 11,250 13,500 16,200 18,900 20,200 20,700 13,200 24.90 0.0 0.505 2.03 5.08 10.16 15.24 21.80 The dimensions of the cylindrical specimen were initial length L₁= 50.8 mm and initial area A₁ = 35.8 mm² and the area at fracture was Ar = 10.0 mm². Plot the stress-strain diagram and determine the following: a) Modulus of elasticity b) The yield strength at a strain offset of 0.002 c) Ultimate strength d) Fracture strength
Table Q4 belowindicates results on a tensile test of a mild steel specimen. 95 kN Proportional Limit load Original diameter Original ga uge length 30 mm 50 mm Yield Point Load 100 kN Extension at proportional limit 0.050 mm Maximum recorded load 160 kN Final length between gauge points 58.8 mm Final minimum diameter 17.9 mm Table Q4 Calculate the following: a. Modulus of Elasticity for the mild steel. b. The proportional limit stress. C. The ultimate tensile strength. d. The percentage elongation. e. The percentage reduction in area.
The data illustrated below have been determined while the tension test of the stainless steel sample by amateur engineers. The gage length of the stainless steel sample was 50.8 mm (2.0in.) and, the original diameter of the steel sample was 12.8 mm (0.505in.). Load (Ib) Elongation (in.) Load (Ib) Elongation (in.) 14000 0.020 2 310 0.0022 14400 0.025 4 640 0.0044 14 500 0.060 6950 0.0066 14600 0.080 9 290 0.0088 14800 0.100 11 600 0.0110 14 600 0.120 13000 0.0150 13600 Fracture With the help of Excel, plot the stress-strain diagram for this test conducted, and define the following mechanical properties: a) Young modulus; b) Proportional limit; c) Yield stress @0.2% offset; d) ultimate stress; e) nominal rupture stress.