Q1: The figure below represents a circular curve having coordinates given in the Table The chainage/station of PC is 20+79.33 m. Calculate: 1. The curve length (L), Chord (C), and deflection angle. 2. Lay out 20m (X) using tangent-offset method and Chord-offset method. 3. Coordinates of station 21+10. Point PC PI O Easting (m) 247.626 278.049 349.45 Northing (m) 425.902 616.457 349.45

Q1: The figure below represents a circular curve having coordinates given in the Table The chainage/station of PC is 20+79.33 m. Calculate: 1. The curve length (L), Chord (C), and deflection angle. 2. Lay out 20m (X) using tangent-offset method and Chord-offset method. 3. Coordinates of station 21+10. Point PC PI O Easting (m) 247.626 278.049 349.45 Northing (m) 425.902 616.457 349.45

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Please help me answer this
Subject: Surveying 2.1 Please show your correct/detailed solution.
%3D A horizontal curve has a radius of 980.80 ft.; an I = 23°00'00"; and, PC Station %3D 76+68.50 ft. Determine: • Deflection angle from the PC to station 79+00.00 ft. = Provide the answer in degrees, minutes, and seconds. Provide whole numbers and do not include units. • Chord length from the PC to station 79+00.00 ft.= Provide your answer to two decimal places and do not include units. • Straight line distance from the PC to the PI = Provide %3D your answer to two decimal places and do not include units.
Topic: Surveying (8)
Two lines XV and YV intersect at an inaccessible point V. Two points A and B are selected on lines XV and YV respectively. Length of AB = 180 m, angle XAB =110°, and angle ABY = 130°. The two straights are to be joined by a curve of 500 m radius. The stationing of point A is 2+500. Calculate the following: a. distance VA b. distance VB c. tangent lengths d. distance XA e. distance YB f. stationing of beginning of the curve g. length of the curve h. stationing of end of the curve
SIMPLE CURVE BEARING OF Point of Curvature - V = N 60° E BEARING OF V - Point of Tangency = S 70° E DEGREE OF CURVE (D) = 05° STATION V = 12 + 234.50 COMPUTE THE FOLLOWING: A. TANGENT DISTANCE B. EXTERNAL DISTANCE C. MIDDLE ORDINATE D. LENGTH OF CURVE E. LONG CHORD F. STATIONING POINT OF CURVATURE AND POINT OF TANGENCY
I need to solve the question please
with illustration please thank you
Simple Curve A railway curve is to connect intersecting tangents with the following design data: Back tangent = N 20° 25' E Forward tangent = S 49°35' E Degree of curve = 5⁰ Design speed = 70 Kph Station PI = 5+555.55 1.Determine the length of line from PC to Pl. a) 234.67m b) 244.67m 2.Compute the straight distance from PC to PT. a) 402.34m b) 375.60m c) 245.89m d) 327.42m c) 389.78m d) 423.67m 3. If the width of the land intended for the railway is 10m, determine the area of land from PC to PT. a) 4,456.56 sqm b) 3,456,43 sqm c) 5,112.34 sqm d) 4,399.92 sqm 4.How long would a 300m long train able to leave the curve completely. a) 25.67 sec b) 38.06m sec c) 40.34 sec d) 29.67 sec
Two tangents intersect at a chainage of 1190m, the deflection angle being 36o. Calculate all the data necessary for setting out a curve of radius 300m using: Offset from long chord method, Offset from tangent (Radial and Perpendicular both) Offsets from chords produced method. Deflection angle method Length of long chord is 100m and peg interval may be taken as 30m. Make figures with each method seperately.
1. A proposed road bend along a highway construction project is to be laid out such that it will be a circular simple curve tangent to the three reference lines DA, AB, and BC. From the given data below, calculate for the following. a. radius of the simple curve b. stationing of PC if V is at 12 + 340 c. stationing of PT POINT LATITUDE DEPARTURE A - 29.34 - 128.76 B - 177.97 - 58.39 Bearing DA = S65°01'50"E Bearing CB = N54°24'10"E
Question 1 A highway survey PI falls in a pond, so a cut off line AB = 275.21 ft is run between the tangents. In the triangle formed by points A, B, and PI, the angle at A = 16°28' and at B = 22°16'. The station of A is 54 + 92.30. Calculate and tabulate curve notes to run, by deflection angles and incremental chords, a 4°30' (arc definition) circular curve at full-station increments to connect the tangents.