Q1 Segment 1 Qt Qt Q2 Segment 2 a. In the simple loop shown above, using the formula for friction factor derive the formula for Q1 as a function of total flow Qt and pipe segments Li and L2. Assuming C and D are identical. b. Calculate Q1 for Qt = 600 gpm, L1 = 400ft, L2 = 200 ft. Does your answer make sense in view of f? Explaint %3D %3D C.
Q1 Segment 1 Qt Qt Q2 Segment 2 a. In the simple loop shown above, using the formula for friction factor derive the formula for Q1 as a function of total flow Qt and pipe segments Li and L2. Assuming C and D are identical. b. Calculate Q1 for Qt = 600 gpm, L1 = 400ft, L2 = 200 ft. Does your answer make sense in view of f? Explaint %3D %3D C.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Hazen Williams formula is one of the most popular friction loss formulas.
Derived from flow tests performed within underground water mains around
1905 by Allen Hazen and Gardner Williams, this friction loss formula was built
on the established work of Antoine de Chezy (1775)
f = 4.552 x Q1.85 / C1.85 x D4.87
where:
f = friction loss of 1 foot of pipe (psi/ft)
Q = flowrate in gpm
C = Hazen-Williams Roughness Coefficient (Higher value smoother pipe)
D = Internal Diameter of Pipe (in)
To obtain the total friction loss in apipe segment, this is multiplied by the pipe
segment, L (ft).
Q1 Segment 1
Qt
Qt
Q2 Segment 2
a. In the simple loop shown above, using the formula for friction factor
derive the formula for Q1 as a function of total flow Qt and pipe
segments L1 and L2. Assuming C and D are identical."
b. Calculate Q1 for Qt = 600 gpm, L1 = 400ft, L2 = 200 ft.
Does your answer make sense in view of f? Explaint
C.
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