Q1 If the key is 110100001 where, If ki=0, then Si (x)=((1 1 0 | 0 1 1 | 100 ))x+((1 1 1)) and If ki=1, then Si (x)=((0 1 1 | 101 | 100))x+((0 1 1)) then the output of the SP network for the plaintext: 101110001 is a) 010110011 b) 111000011 c) 110110111 d) 010110110 Q.2 If the key is 110100001, the output of the SP network for the plaintext: 101110001 is a) 110100011 b) 110101110 c) 010110111 d) 011111010
Q1 If the key is 110100001 where, If ki=0, then Si (x)=((1 1 0 | 0 1 1 | 100 ))x+((1 1 1)) and If ki=1, then Si (x)=((0 1 1 | 101 | 100))x+((0 1 1)) then the output of the SP network for the plaintext: 101110001 is a) 010110011 b) 111000011 c) 110110111 d) 010110110 Q.2 If the key is 110100001, the output of the SP network for the plaintext: 101110001 is a) 110100011 b) 110101110 c) 010110111 d) 011111010
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Encryption and write the steps on a piece of paper please
![Assignment.1
Q1
If the key is 110100001 where,
If ki=0, then Si (x)=((1 1 0 | 0 1 1 | 100 ))x+((1 1 1))
and If ki=1, then Si (x)=((0 11 | 101 | 100))x+((0 1 1))
then the output of the SP network for the plaintext: 101110001 is
a) 010110011
b) 111000011
c) 110110111
d) 010110110
Q.2
If the key is 110100001, the output of the SP network for the plaintext:
101110001 is
a) 110100011
b) 110101110
c) 010110111
d) 011111010
:Note
. The permutation function is given an output 036147258 to an input 12345678
.Any result without a proof: diagram and calculation, will not be considered](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7af17475-e50d-49c6-b4c0-4225b5e8438a%2F612ebbbc-c31c-4588-ab06-e8cdf8252c47%2Fqsp3cjq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Assignment.1
Q1
If the key is 110100001 where,
If ki=0, then Si (x)=((1 1 0 | 0 1 1 | 100 ))x+((1 1 1))
and If ki=1, then Si (x)=((0 11 | 101 | 100))x+((0 1 1))
then the output of the SP network for the plaintext: 101110001 is
a) 010110011
b) 111000011
c) 110110111
d) 010110110
Q.2
If the key is 110100001, the output of the SP network for the plaintext:
101110001 is
a) 110100011
b) 110101110
c) 010110111
d) 011111010
:Note
. The permutation function is given an output 036147258 to an input 12345678
.Any result without a proof: diagram and calculation, will not be considered
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