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Q1 For the pin-jointed truss shown below, with a vertical load applied at joint 1, determine: (i) The magnitude of the force in each of the three members and state whether they are in compression or tension (ii) The magnitude and direction of the reactions at the supports 2 60⁰ 60° 100 KN 60⁰ 3

Q1 For the pin-jointed truss shown below, with a vertical load applied at joint 1, determine: (i) The magnitude of the force in each of the three members and state whether they are in compression or tension (ii) The magnitude and direction of the reactions at the supports 2 60⁰ 60° 100 KN 60⁰ 3

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Please answer the truss problem shown in image

the answers are:

(i) F1-2 = 58 kN (compression) F1-3 = 58 kN (compression) F2-3 = 29 kN (tension)
(ii) R2=R3=50 kN vertically upwards 

I have also attached my working out as i am not sure where i am going wrong in my calculations.

Q1 For the pin-jointed truss shown below, with a vertical load applied at joint 1, determine: (i) The magnitude of the force in each of the three members and state whether they are in compression or tension (ii) The magnitude and direction of the reactions at the supports 2 60⁰ 60° 100 KN 60⁰ 3
Transcribed Image Text:Q1 For the pin-jointed truss shown below, with a vertical load applied at joint 1, determine: (i) The magnitude of the force in each of the three members and state whether they are in compression or tension (ii) The magnitude and direction of the reactions at the supports 2 60⁰ 60° 100 KN 60⁰ 3
F12 Cos 60- ↓ F₁₂ singo 60° fi 8 100 Fizsin60 + 60 F12 100 F₁₂sin601 F₁3sin 60 F12 cos 40 C05660 100nN 100 = F1251460 + F12 100 = F₁₂ (sin 60+ 1) 60° → Fięcos 60 ↓ Fising F₁3 F1₂ C0560 = F13 COS 60 F12 COS 60 (0)60 = F₁3 - F₁2 = 54N and F 13 = 54N since F₁2 = F13
Transcribed Image Text:F12 Cos 60- ↓ F₁₂ singo 60° fi 8 100 Fizsin60 + 60 F12 100 F₁₂sin601 F₁3sin 60 F12 cos 40 C05660 100nN 100 = F1251460 + F12 100 = F₁₂ (sin 60+ 1) 60° → Fięcos 60 ↓ Fising F₁3 F1₂ C0560 = F13 COS 60 F12 COS 60 (0)60 = F₁3 - F₁2 = 54N and F 13 = 54N since F₁2 = F13
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