Q1 For the pin-jointed truss shown below, with a vertical load applied at joint 1, determine: (i) The magnitude of the force in each of the three members and state whether they are in compression or tension (ii) The magnitude and direction of the reactions at the supports 2 60⁰ 60° 100 KN 60⁰ 3
Q1 For the pin-jointed truss shown below, with a vertical load applied at joint 1, determine: (i) The magnitude of the force in each of the three members and state whether they are in compression or tension (ii) The magnitude and direction of the reactions at the supports 2 60⁰ 60° 100 KN 60⁰ 3
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
Please answer the truss problem shown in image
the answers are:
(i) F1-2 = 58 kN (compression) F1-3 = 58 kN (compression) F2-3 = 29 kN (tension)
(ii) R2=R3=50 kN vertically upwards
I have also attached my working out as i am not sure where i am going wrong in my calculations.

Transcribed Image Text:Q1
For the pin-jointed truss shown below, with a vertical load applied at joint 1, determine:
(i) The magnitude of the force in each of the three members and state whether they are in
compression or tension
(ii) The magnitude and direction of the reactions at the supports
2
60⁰
60°
100
KN
60⁰
3

Transcribed Image Text:F12 Cos 60-
↓ F₁₂ singo
60°
fi
8
100 Fizsin60 +
60
F12
100 F₁₂sin601 F₁3sin 60
F12 cos 40
C05660
100nN
100 = F1251460 + F12
100 = F₁₂ (sin 60+ 1)
60°
→ Fięcos 60
↓ Fising
F₁3
F1₂ C0560 = F13 COS 60
F12 COS 60
(0)60
= F₁3
- F₁2 = 54N and F 13 = 54N since F₁2 = F13
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