Q1) Find the capacitanee (in pF) of parallel-plate capacitor containing two dielectries with e1 = 3 and Erz = 4.5, each comprising one-half the volume. The area of the plates is 20 cm and the distance between them is 1 cm.
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- In reference to the load, how are capacitors connected to help prevent voltage spikes and surges? Are capacitors connected in parallel or in series with the load?4. In what form is the energy of a capacitor stored?The plates of a parallel-plate capacitor are square and have the length of one side. 20 cm and the distance between the plates is 0.5 cm. The material between the plates is air.What is the capacitance of a parallel plate capacitor in farads?
- (6) A parallel-plates capacitor with plate area of 100 cm? has a separation of 3mm between the pates. The separation is divided into three slabs, where each slab has 1 mm distance. The first slab is filled by air and has a constant of 1. The second slab is filled by polystyrene and has a constant of 2.5, while the third slab is filled by silicon dioxide and has a constant of 4. Compute the capacitance of the system. Note: for parallel slabs; Conductor 1 E = T 1 Air E1 83 Material A Material 3 Conductor Ans. C = 54 pF.i. In a parallel plate capacitor, the cross sectional area of the plates are doubled and all other parameters remains the same. The ratio of Final capacitance to initial capacitance is found to be:If this were actually a parallel plate capacitor, which would be the dielectric constant of the dielectric? assume the capacitor has plate that are 2.50 mm by 2.25 mm, and the plates are separated by a distance of 3.30 mm.
- Suppose the space between the plates of the capacitor is filled with equal thickness of the same dielectrics but arranged as shown in the figure. Eachhaving an area of 8.0x10 -4 m 2 and separated from each otherby 5.0 mm. Half of the space between the plates is filled withglass and the other with mica. What is its capacitance?3.1 A capacitor is made up of two dielectric materials A and B of relative permittivity of 2.5 and 4, and thickness 1 mm and 3 mm respectively connected in series. 3.1.1 If the cross-section of each dielectric is 500 mm2 determine the total capacitance.9 When a dielectric material is inserted between the parallel plates, what will happen to the value of capacitance? Select one: a. Capacitance will remains the same. b. Capacitance will increase. c. Capacitance will decrease. d. Capacitance will become zero.
- QUESTION 5 A 20 ohms resistor is connected in series with a capacitor of 0.01 farad and an emf in volts given by 40e-3¹ +20e-6. Assuming that the charge and current on the capacitor are zero at t=0, determine the charge and current at any time.Give the reason why a dielectric material increases capacitance compared with what it would be with air between the plates of a capacitor.Two identical parallel plate capacitors of plate area A and plate separation d are in series connected to a constant voltage AV = 16V as shown in the figure 1. After the capacitors are fully charged the switch is opened and a dielectric slab of dielectric constant x = 3.0, thickness d and the surface area A/2 is placed between the plates of the capacitor C₂ as shown in the figure 2. What is the voltage across the capacitors (IV, - Val) (Volt)? a) 12 b) 7 C) 15 d) 21/2 e) 6 바람 Figure 1 AV Figure 2 A/2 ΔΙ C₂ S