Q1) Determine the magnitude and direction of F; so that If the resultant of the three forces act on the bracket has a magnitude of 250 N and a direction of 20° measured clockwise from the positive x axis. (F 100 N 13 12 F:= 150 Rx = 250 cos20 = 234.923 N R, =R = F, : +150+F3 cos 0 13 + 150 + F3 cos 0 = 234.923 13 = 100 * - 46.461 F3 cos e .(1)

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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1 من إجمالي 2
Q1) Determine the magnitude and direction of F3
so that If the resultant of the three forces act on
the bracket has a magnitude of 250 N and a
direction of 20° measured clockwise from the
Fi = 100 N
positive x axis.
12
F2 = 150
Ry = 250 cos20 = 234.923 N
Rx = > F = F, *
5
+ 150 + F3 cos 0
%3D
13
F3
Ry = 100 *
+ 150 + F, cos 0 = 234.923
13
46.461
F =
(1)
cos e
Ry = 250 sin20 = -85.505 N
12
Ry = E = F, +
- F sin e
13
12
Ry = 100 *
- F sin e = - 85.505
13
Fsine = 177.812
(2)
Sub. 1 in 2
46.461
sine = 177.812
cos e
tane = 3.827
e = 75.356°
F = 183.776 N
Transcribed Image Text:1 من إجمالي 2 Q1) Determine the magnitude and direction of F3 so that If the resultant of the three forces act on the bracket has a magnitude of 250 N and a direction of 20° measured clockwise from the Fi = 100 N positive x axis. 12 F2 = 150 Ry = 250 cos20 = 234.923 N Rx = > F = F, * 5 + 150 + F3 cos 0 %3D 13 F3 Ry = 100 * + 150 + F, cos 0 = 234.923 13 46.461 F = (1) cos e Ry = 250 sin20 = -85.505 N 12 Ry = E = F, + - F sin e 13 12 Ry = 100 * - F sin e = - 85.505 13 Fsine = 177.812 (2) Sub. 1 in 2 46.461 sine = 177.812 cos e tane = 3.827 e = 75.356° F = 183.776 N
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