Q1) Determine the magnitude and direction of F; so that If the resultant of the three forces act on the bracket has a magnitude of 250 N and a direction of 20° measured clockwise from the positive x axis. (F 100 N 13 12 F:= 150 Rx = 250 cos20 = 234.923 N R, =R = F, : +150+F3 cos 0 13 + 150 + F3 cos 0 = 234.923 13 = 100 * - 46.461 F3 cos e .(1)
Q1) Determine the magnitude and direction of F; so that If the resultant of the three forces act on the bracket has a magnitude of 250 N and a direction of 20° measured clockwise from the positive x axis. (F 100 N 13 12 F:= 150 Rx = 250 cos20 = 234.923 N R, =R = F, : +150+F3 cos 0 13 + 150 + F3 cos 0 = 234.923 13 = 100 * - 46.461 F3 cos e .(1)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
![1 من إجمالي 2
Q1) Determine the magnitude and direction of F3
so that If the resultant of the three forces act on
the bracket has a magnitude of 250 N and a
direction of 20° measured clockwise from the
Fi = 100 N
positive x axis.
12
F2 = 150
Ry = 250 cos20 = 234.923 N
Rx = > F = F, *
5
+ 150 + F3 cos 0
%3D
13
F3
Ry = 100 *
+ 150 + F, cos 0 = 234.923
13
46.461
F =
(1)
cos e
Ry = 250 sin20 = -85.505 N
12
Ry = E = F, +
- F sin e
13
12
Ry = 100 *
- F sin e = - 85.505
13
Fsine = 177.812
(2)
Sub. 1 in 2
46.461
sine = 177.812
cos e
tane = 3.827
e = 75.356°
F = 183.776 N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F50440fba-8528-46f3-9d07-957f43172fe8%2Fdf670dfc-fd05-4708-875e-b711e74d535d%2Fm8985kl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1 من إجمالي 2
Q1) Determine the magnitude and direction of F3
so that If the resultant of the three forces act on
the bracket has a magnitude of 250 N and a
direction of 20° measured clockwise from the
Fi = 100 N
positive x axis.
12
F2 = 150
Ry = 250 cos20 = 234.923 N
Rx = > F = F, *
5
+ 150 + F3 cos 0
%3D
13
F3
Ry = 100 *
+ 150 + F, cos 0 = 234.923
13
46.461
F =
(1)
cos e
Ry = 250 sin20 = -85.505 N
12
Ry = E = F, +
- F sin e
13
12
Ry = 100 *
- F sin e = - 85.505
13
Fsine = 177.812
(2)
Sub. 1 in 2
46.461
sine = 177.812
cos e
tane = 3.827
e = 75.356°
F = 183.776 N
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