Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How is a 12-bit memory address divided into tag, line number, and byte number? Block size =8byte (2³), so 3bits. Cache of 32 lines (25), so 5bits. TAG LINES WORD 4 5 3 Into what line would bytes with each of the following addresses be stored? 0001 0001 0001 TAG LINES WORD 0001 00010 001 Line: 1 0011 0011 0100 TAG LINES WORD 0011 00110 100

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A: Proof by contradiction.

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A: In step 2, I have provided  CORRECT OPTION along  with  brief explanation--------------

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