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Q1: Choose the correct Answer: 1- The linear system A) uniqe solusion E) Three solution 02: Iteration the x-3y = 2 2x-6y=4 has B) Two solution C) no solution D) infinity soutions F) Not one of the previous 1) using

Q1: Choose the correct Answer: 1- The linear system A) uniqe solusion E) Three solution 02: Iteration the x-3y = 2 2x-6y=4 has B) Two solution C) no solution D) infinity soutions F) Not one of the previous 1) using

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Q1: Choose the correct Answer: 1- The linear system x-3y = 2 2x - 6y = 4 has A) uniqe solusion B) Two solution C) no solution D) infinity soutions F) Not one of the previous E) Three solution Q2: Iteration three of the root equation x3-x-1=0 belonging in the interval (1,2) using bisection method is A) 1.5 B) 1.3 C) 1.25 D) 1.35 E) 1.375 F) 1.357 Q3: Iteration 2 by Gauss-Seidel iteration method, where x = x3 = 0 are -2x1 + 7x2 + 2x3 = 5 6x12x2 + x3 = 11 x1 + 2x2 - 5x3 = -1 x 1.0107 A) X₁=2.0691 X₂= 1.0121 B) X₂=2.0691 C) X₁=3.0691 X₂= 1.1021 x₁=1.0157 D) X₁=2.7691 E) X₁ 2.0611 x₂= 2.0021 x₁=1.4147 F) X₁=2.0691 (0) = x₂ x₂= 1.0122 x₁=1.0147 X₂= 1.0221 x₁=1.2147 x₂= 1.0021 x₁=1.0147 +0)
Transcribed Image Text:Q1: Choose the correct Answer: 1- The linear system x-3y = 2 2x - 6y = 4 has A) uniqe solusion B) Two solution C) no solution D) infinity soutions F) Not one of the previous E) Three solution Q2: Iteration three of the root equation x3-x-1=0 belonging in the interval (1,2) using bisection method is A) 1.5 B) 1.3 C) 1.25 D) 1.35 E) 1.375 F) 1.357 Q3: Iteration 2 by Gauss-Seidel iteration method, where x = x3 = 0 are -2x1 + 7x2 + 2x3 = 5 6x12x2 + x3 = 11 x1 + 2x2 - 5x3 = -1 x 1.0107 A) X₁=2.0691 X₂= 1.0121 B) X₂=2.0691 C) X₁=3.0691 X₂= 1.1021 x₁=1.0157 D) X₁=2.7691 E) X₁ 2.0611 x₂= 2.0021 x₁=1.4147 F) X₁=2.0691 (0) = x₂ x₂= 1.0122 x₁=1.0147 X₂= 1.0221 x₁=1.2147 x₂= 1.0021 x₁=1.0147 +0)
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