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- 60° 30° A 50 kg truck engine is lifted using the setup shown. Assuming that the pulleys are frictionless, What force P must be applied to the cable to hold the engine in the position shown with d= 1m? (Hint: because the frictionless pulleys, the tension in the cable will be uniform through out the whole length of the cable.) 2. 3. d 30 kg 600 N/m A 3m 3m Determine the reactions at A and B. 50 kgA 1,040-N crate is being pushed across a level floor at a constant speed by a force F of 390 N at an angle of 20.0° below the horizontal, as shown in the figure a below. Two figures show a side view of a crate positioned upon a horizontal surface. Figure (a): An arrow pointing downward and to the right is labeled vector F and forms an angle of 20° below the horizontal as it approaches the upper left edge of the crate. Figure (b): An arrow pointing upward and to the right is labeled vector F and forms an angle of 20° above the horizontal as it extends from the upper right edge of the crate. (a) What is the coefficient of kinetic friction between the crate and the floor? (Enter your answer to at least three decimal places.)(b) If the 390-N force is instead pulling the block at an angle of 20.0° above the horizontal, as shown in the figure b, what will be the acceleration of the crate? Assume that the coefficient of friction is the same as that found in part (a).PRINTER VERSION 4 ВАСК NEXT Chapter 11, Problem 026 Your answer is partially correct. Try again. At the instant of the figure, a 3.00 kg particle P has a position vector r of magnitude 4.10 m and angle 0, = 41.0° and a velocity vector v of magnitude 7.60 m/s and angle e, = 30.0°. Force F, of magnitude 2.10 N and angle 03 = 30.0° acts on P. All three vectors lie in the xy plane. About the origin, what are the magnitude of (a) the angular momentum of the particle and (b) the torque acting on the particle? (a) Number Units kg-m^2/sv (b) Number UnitsTN-m Click if you would like to Show Work for this question: Open Show Work