I need the correct answer. Don't give wrong. Q1)assumptions and comment every line of your code. Assume that the base address of int arrayarX is at $s0 and n is at $s1. Functions sum/sqr take arguments $a0, Ša1, and return theresult in Sv0. Use the following registers for variables sm =St0, i=$t1.Compile the following C/JAVA program into MIPS. Write down all yourmain (XIl arX int arraysarX[0]= sqr(arX, n);int sum(int] a, int nXint sm 0;for (int i =0; ik n; i++)sm += a[i):retum sm;int sqr (int] a, int n)Xint c = sum(a.n):return c'c;

I'm providing the MIPS code as well as an output screenshot from your given code. I hope this will…

Q1) assumptions and comment every line of your code. Assume that the base address of int array arX is at $s0 and n is at $s1. Functions sum/sqr take arguments $a0, $a1, and return the result in $v0. Use the following registers for variables sm =$t0, i=St1. Compile the following C/JAVA program into MIPS. Write down all your main (X Il arX int arrays arX[0]= sqr(arX, n): int sum(int] a, int nX int sm = 0; for (int i =0; i< n; i++) sm += a[i): retum sm; int sqr (int] a, int n){ int c = sum(a.n): return c"c;