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Q1 - Assuming that a Map collection is called "courseMap". It holds records of courseNo and courseName. Write ONE statement to retrieve ONLY the course numbers?

Q1 - Assuming that a Map collection is called "courseMap". It holds records of courseNo and courseName. Write ONE statement to retrieve ONLY the course numbers?

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Answer the following questions in detail in a short, correct and accurate answer with justification for each answer: Q1 - Assuming that a Map collection is called "courseMap". It holds records of courseNo and courseName. Write ONE statement to retrieve ONLY the course numbers? Ans : Q2 - Write ONE statement to create an Anonymous Inner Class (consider the class is empty!)? Ans: *Choose the correct answer and justify your answer : Q3 - To explore for all files in directory X, you would write: A. Files.readAllFiles(Paths.get("E/X")) B. Fles.newlnputStream(Paths.get("E:/X")) OC new Scanner(new File("E:X)) D. Files.newDirectoryStream(Paths.get(EX)) DE E.Files.newBufferedStream(Paths.get("EX"))
Transcribed Image Text:Answer the following questions in detail in a short, correct and accurate answer with justification for each answer: Q1 - Assuming that a Map collection is called "courseMap". It holds records of courseNo and courseName. Write ONE statement to retrieve ONLY the course numbers? Ans : Q2 - Write ONE statement to create an Anonymous Inner Class (consider the class is empty!)? Ans: *Choose the correct answer and justify your answer : Q3 - To explore for all files in directory X, you would write: A. Files.readAllFiles(Paths.get("E/X")) B. Fles.newlnputStream(Paths.get("E:/X")) OC new Scanner(new File("E:X)) D. Files.newDirectoryStream(Paths.get(EX)) DE E.Files.newBufferedStream(Paths.get("EX"))
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