Q1: A: Calculate the solubility product constant for PbCl2, if 80.0 mL of a saturated solution of PbCl was found to contain 0.3408 g of PbCl2 dissolved in it? Discuss your results. (Solubility in 0.3408g/50 mL) PbCl26) → Pb*2(aq) +2CI°(aq) B: What is the pH of 0.6 M NH.Cl solution? Discuss your results. (Kb of NH= 1.8 x 105) NH4 + H2O+→ H3O* +NH3

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Q1: A: Calculate the solubility product constant for PbCl2, if 80.0 mL of a saturated solution of
PbCl was found to contain 0.3408 g of PbCl2 dissolved in it? Discuss your results.
(Solubility in 0.3408g/50 mL)
PbCl26) → Pb*²(aq) +2CI°(aq)
B: What is the pH of 0.6 M NH,Cl solution? Discuss your results. (Kb of NH= 1.8 x 105)
NH,+ + H2O+→ H3O* +NH3
Transcribed Image Text:Q1: A: Calculate the solubility product constant for PbCl2, if 80.0 mL of a saturated solution of PbCl was found to contain 0.3408 g of PbCl2 dissolved in it? Discuss your results. (Solubility in 0.3408g/50 mL) PbCl26) → Pb*²(aq) +2CI°(aq) B: What is the pH of 0.6 M NH,Cl solution? Discuss your results. (Kb of NH= 1.8 x 105) NH,+ + H2O+→ H3O* +NH3
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