Q.7 (a) A 500 mm diameter bored concrete pile is to be formed in the soil profile as shown in figure. The ground conditions are as follows: Granular soil: Dense gravel: Glacial clay: Y = 20 kN/m³ ' = 22.5° K = 1.0 Y = 21 kN/m³ '=26.25° K₁ = 2.0 Y= 20 kN/m³

Q: (m) Calculate distance XY shown in Figure 3 over which surcharge load S'applied. The angle of the…

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Q: Use the stress-strain curve, where shear stress and strain response are obtained at different…

A: Detailed solution is provided belowPlease read carefullyThank you. Explanation:Step 1:Step 2: Step…

Q: Two footings rest in a layer of sand 2.7 m thick. The bottoms of the footings are 0.90 m below the…

A: ANSWER:- 64.6 Which is approximately equal to 69.2 mm So , option (A) IS correct answer…

Q: 11.26 Figure P11.26 shows a group pile in clay. Determine the consolidation settlement of the group.…

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Q: An embankment load of 500 kg/cm²

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Q: An element of soil at the point of failure is represented as a square with effective stresses…

A: Solution: Centre of Mohr's Circle  C=σa'+σb'2,0C=54+202,0=37,0

Q: The following is a sketch of the proposed embankment, calculate the addition of vertical stress…

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Q: 1. Find the increase of pressure at point A due to loading q=400 kN/m² on the given rectangular…

A: Given data in question  Intensity 400 kN/m2 Dimensions 8×4 m To find out  Increase in pressure at A

Q: d 8.16 An irregularly shaped footing shown in the figure is loaded with 60 kN/m² uniform load on the…

A: To compute the vertical stress increment under Point A at a depth of z=4z = 4z=4 m for the given…

Q: A soil profile is shown in Figure 7.28. An embankment load of 500 kg/cm² is placed on the ground…

A: Given data h = 26ft p = 500kg/cm2 first change the units: 500X2048 = 1.06 X 106lb/ft2

Q: Problem Number 2: A soil profile is shown in the figure below, a uniformly distributed load (A6) at…

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Q: The excavation was being done for a foundation trench in a plastic clay having a unit weight of 2.3…

A: Plastic clay- unit weight γ=2.3 gm/ccDepth of excavation Hc=4 m,ϕ=0o

Q: Design Procedure D y = 100 lb/ft³ ka = 0.3 kp = 3.0 Pp Z₁ Zp 4 2 Za Z Ap Solve for D Pa 1 2 3 4 0…

A: A cantilever retaining sheet pile is given and active and passive earth pressure is acting on it.

Q: Laplace equation for the flow of water through a soil is given by Ha²H JH +- + дх² ду² д22 Assume…

A: Boundary conditions,At x= , H= 5 m and

Q: A group pile in clay is shown in the figure below. Determine the maximum vertical load Qg be applied…

A: Different soils strata and their properties are given.  To find maximum permissible vertical load,…

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.