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Q.6: Given R1=102, R=150, R=22Q and Re=330, find the current flowing through resistance R4. ww R2 R1 8.OV Ra R3 ww 12.0V

Q.6: Given R1=102, R=150, R=22Q and Re=330, find the current flowing through resistance R4. ww R2 R1 8.OV Ra R3 ww 12.0V

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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ww Q.6: Given R1=102, R2=150, R=22Q and R=330, find the current flowing through resistance R4. ww R2 R1 8.0V R3 ww 12.0V
Transcribed Image Text:ww Q.6: Given R1=102, R2=150, R=22Q and R=330, find the current flowing through resistance R4. ww R2 R1 8.0V R3 ww 12.0V
Expert Solution
Step 1

Given: the resistances are:

R1 =10Ω;  R2 =15Ω;  R3 =22Ω;  R4 =33Ω

Now using the Kirchhoff's junction rule i.e. current entering equals the current out of any junction point:

Physics homework question answer, step 1, image 1

Using Kirchhoff's loop rule in ABEFA i.e. "the net voltage drop across any closed loop is zero"

12 +8 =33I'+10i           =33I'+10(I+I')     20  = 10 I +43I'                                         ....1      

Using Kirchhoff's loop rule in BCDEB i.e. "the net voltage drop across any closed loop is zero"

8  = 22 I +15I-33I' 8 =37I-33I'                                         ....2    

 

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