Q.3: Forty two students are in a given course section: (1) What is the probability that exactly two of the students have the same birth date? (1I) What is the probability that no two students have the some birth month? Q.4: The probability that 5 persons can have different birth month is: (A) 4.823 * 10-4 (B) 1 – 4.823 * 10-4 (C) 0.382 (D) 0.618 (E) (F) None of these.

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Q.3: Forty two students are in a given course section: (1) What is the probability that exactly two of the students have the same birth date? (1I) What is the probability that no two students have the some birth month? Q.4: The probability that 5 persons can have different birth month is: (A) 4.823 * 10-4 (B) 1 – 4.823 * 10-4 (C) 0.382 (D) 0.618 (E) (F) None of these.
Q.3: Forty two students are in a given course section:
(1) What is the probability that exactly two of the students have the same birth date?
(1I) What is the probability that no two students have the some birth month?
Q.4: The probability that 5 persons can have different birth month is:
(A) 4.823 + 10-4
(B) 1 – 4.823 + 10-4
(C) 0.382
(D) 0.618
(E)
(F) None of these.
NIM
Transcribed Image Text:Q.3: Forty two students are in a given course section: (1) What is the probability that exactly two of the students have the same birth date? (1I) What is the probability that no two students have the some birth month? Q.4: The probability that 5 persons can have different birth month is: (A) 4.823 + 10-4 (B) 1 – 4.823 + 10-4 (C) 0.382 (D) 0.618 (E) (F) None of these. NIM
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