Q.2. A five-sided closed field traverse has the following angles: A=(101°03'39");B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E =(118°55'49"). The lengths of thesides are as follows: AB = 51.766m; BC=26.947m; CD=37.070m; DE =35.292m;EA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is notscaled.B26.947 m101° 42' 09"51.766 mC102° 22' 23"A101° 03' 39"118° 55' 49"E115° 57' 40"35.292 md)If the coordinates of station A are (1000.000 N, 1000.000 E), compute thecoordinates of “C" station.e)Compute the area enclosed by the traverse using the coordinate method.19.192 m37.070 m

traverse survey - length and bearing both are measured for different line of a traverse. the…

Q.2. A five-sided closed field traverse has the following angles: A=(101°03'39"); B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E=(118°55'49"). The lengths of the sides are as follows: AB = 51.766m; BC=26.947m; CD=37.070m ; DE =35.292m; EA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not scaled. 26.947 m 101° 42' 09" 51.766 m 102° 22' 23" A 101° 03' 39" 118° 55' 49" 19.1 .070 m

Q.2. A five-sided closed field traverse has the following angles: A=(101°03'39"); B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E=(118°55'49"). The lengths of the sides are as follows: AB = 51.766m; BC=26.947m; CD=37.070m ; DE =35.292m; EA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not scaled. 26.947 m 101° 42' 09" 51.766 m 102° 22' 23" A 101° 03' 39" 118° 55' 49" 19.1 .070 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Unit Conversion

Standard units are also called SI units. SI units are used for measuring a physical quantity satisfying certain conditions. There are two types of units: fundamental units and derived units. Fundamental units are physical quantities that are independent, that is, they do not depend on other quantities like mass, length, or time. There are plenty of quantities in our lives which need to be measured and compared. Measuring is the comparison of a particular physical quantity with its reference value. A unit is a measure of a fixed physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with.

Question

Q.2. A five-sided closed field traverse has the following angles: A=(101°03'39");
B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E =(118°55'49"). The lengths of the
sides are as follows: AB = 51.766m; BC=26.947m; CD=37.070m; DE =35.292m;
EA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not
scaled.
B
26.947 m
101° 42' 09"
51.766 m
C
102° 22' 23"
A
101° 03' 39"
118° 55' 49"
E
115° 57' 40"
35.292 m
d)
If the coordinates of station A are (1000.000 N, 1000.000 E), compute the
coordinates of “C" station.
e)
Compute the area enclosed by the traverse using the coordinate method.
19.192 m
37.070 m

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11. Determine the unknown bearings for the traverse courses shown in Figure A. 89°38' 0 96 11' N83 39'E 52°42', P
i need the answer quickly
5) [Book problem 7.17] Course AB of a five-sided traverse runs due north. From the given balanced interior angles to the right (A - E as shown below), compute and tabulate the bearings and azimuths from north for each side of the traverse. A = 156°23'53", B = 53°36'08", C = 83°15'58", D = 153°52'00", and E = 92°52'01" (Hints: you are asked to compute the azimuths and bearings of a 5-sided polygon traverse, whose first course, AB, runs due north, and whose balanced interior angles to the right are given. Use the tabular method demonstrated in class.)
Item 7 The observed lengths of the sides (in feet) of a five-sided closed polygon traverse are as follows: AB=201.74, BC = 283.37, CD=497.87, DE = 321.33, and EA 381.28. (Note: Assume units of feet for all distances.) The preliminary azimuths obtained after balancing the angles are as follows: AB=138° 16'27", BC = 67°02′46", CD = 354°22′24", DE = 256° 13'01", EA = 185°29'20". Submit Part C Compute the linear misclosure. Express your answer in feet to three significant figures. Submit IVE ΑΣΦ ↓↑ vec Part D Request Answer 1: Compute the relative precision. Express your answer to three significant figures. Submit Request Answer AΣ vec Request Answer ? ? ft 7 of 9 Review
Consider a five-sided closed polygon traverse. The azimuth of side AB is fixed at 218°59′30″. A = 132°47'06", B = 108°46'18", C = 107°19′37", D = 81°50′36", E = 109°16′18″. (Note: line BC bears SE.) The lengths of the sides (in feet) are as follows: AB = 202.74, BC = 283.87, CD = 498.37, DE = 320.33, and EA = 380.78. The coordinates of station A are X = 20, 000.00 ft and Y = 15,000.00 ft. Part A Compute the area enclosed by the traverse above using DMDs. Express your answer to two significant figures and include appropriate units. Note: Traverse does not need to be adjusted to determine the correct answer.
6.16 See Figure 6.24. The five-sided, closed traverse has the following angles and for 15 distances: B umise los A = 38°30' B = 100°38' C = 149°50 Basigns no 11100D = 85°59' AB= 371.006 m BC = 110.222 m CD = 139.872 m DE 103.119 m E = 165°03' EA = 319.860 m +2- 725121 Moto C D unde Side AB has an azimuth of 306°31'. (a) Perform a check for angular closure. (b) Compute both bearings and azimuths for all sides. (c) Compute the latitudes and departures. 201 Az. = 306°31' E FIGURE 6.24 Sketch for Problem 6.16. A