Q.2 The simply supported steel beam shown in Fig. 2 has a span of s 24 ft. with flange having full lateral restrained from a concrete slab. The uniformly distributed applied dead load D = 1.0 kip/ft and two concentrated live loads PL = 20 kips each acts as shown in the Figure. Using the relevant Design Tables Select a suitable A992 steel (Fy = 50 ksi) W- section to satisfy LRFD Design: P₁= 20 kips 8 ft. 24 ft. FIG. 2 P₁ = 20 kips ↓ a) Strength Design (Flexure and Shear) b) Serviceability (Deflection) k 8 ft. WD = 1.0 kips/ft 38

Q.2 The simply supported steel beam shown in Fig. 2 has a span of s 24 ft. with flange having full lateral restrained from a concrete slab. The uniformly distributed applied dead load D = 1.0 kip/ft and two concentrated live loads PL = 20 kips each acts as shown in the Figure. Using the relevant Design Tables Select a suitable A992 steel (Fy = 50 ksi) W- section to satisfy LRFD Design: P₁= 20 kips 8 ft. 24 ft. FIG. 2 P₁ = 20 kips ↓ a) Strength Design (Flexure and Shear) b) Serviceability (Deflection) k 8 ft. WD = 1.0 kips/ft 38

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Properties of materials

A property of a material describes its characteristics and distinguishes it from the others. The material properties are described it in terms of its hardness, color, appearances, and so on. The material properties generally depend on the type of material, or whether it is a metal or an alloy. There are different kinds of material properties such as mechanical properties, thermal properties, physical properties, and chemical properties. Chemical properties describe the material in terms of a chemical change. The mechanical properties come into existence when the material is acted upon by an external load. Thermal properties are associated with the temperature of the material and specific heat.

Question

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Q.2 The simply supported steel beam shown in Fig. 2 has a span of s 24 ft. with flange having
full lateral restrained from a concrete slab. The uniformly distributed applied dead load D =
1.0 kip/ft and two concentrated live loads PL = 20 kips each acts as shown in the Figure.
Using the relevant Design Tables Select a suitable A992 steel (Fy = 50 ksi) W- section to
satisfy
LRFD
Design:
P₁=20 kips
8 ft.
24 ft.
P₁ = 20 kips
↓
FIG. 2
a) Strength Design (Flexure and Shear)
b) Serviceability (Deflection)
k
8 ft.
WD = 1.0 kips/ft
3

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5. The beam-column has a height of 7.5m and is a member of a braced frame. It is subjected to an axial load of DL-65KN and LL= 1OOKN. It is pinned at both ends. A W12X35 section was used and was made up of A-36 steel with Fy-250MPA. Compute the interaction value for beam- column based on NSCP 2015 code provisions. Ngelect the weight of the section. A = 6645 mm2 Zx- 839x10^3 mm3 d- 317.50mm Sx- 747x10^3 mm3 tw= 7.62 Rx= 133.35 bf= 166.62 ly= 10x10^6 mm4 tf- 13.21 Sy= 122x10^3 mm3 Ix= 119x10^6 mm4 Ry3 39.12mm 3.5 Note: Use C=D1.00%--0.2
The answer is between 18.25 and 20.25
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A W420x85 steel beam is fully restrained with a uniformly distributed live load of 25 kN/m. The beam has a span of 10m. Use A36 steel. Properties of W40 x 85 A = 10839 mm2 %D bf = 180 mm tf = 18 mm %3D tw = = 11 mm Ix = 310 x 106 mm4 %3D d = 420 mm (Note: Since this is a built-up section, for checking of web slenderness, use h = d - 2t;) %3D 1) Calculate the design shear strength of the section. Check if the section is adequate in shear. USE LRFD and U = 1.2D + 1.6L. %3D 2) Is the maximum deflection at the midspan of the beam due to live load adequate? 3) Calculate the maximum uniform live load that can be carried by the beam.