Q.2) Determine the moment about line OB due to the force F shown in figure below. The magnitude of force F is 600 N. 325 mm 400 mm 150 mm 275 mm 350 mm
Q.2) Determine the moment about line OB due to the force F shown in figure below. The magnitude of force F is 600 N. 325 mm 400 mm 150 mm 275 mm 350 mm
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![**Q.2) Determine the moment about line OB due to the force F shown in the figure below. The magnitude of force F is 600 N.**
[Image Description]
The diagram illustrates a vertical cylindrical structure with a horizontal arm pivoted at the top. The following points and dimensions are marked:
- The vertical axis is labeled as the \( z \)-axis.
- The horizontal axis perpendicular to \( z \) and going to the left is labeled as the \( x \)-axis.
- The horizontal axis perpendicular to \( z \) and going to the back is labeled as \( y \).
- Point O marks the origin where the vertical cylinder meets the ground.
- Point B is on the \( x \)-axis at a distance of 150 mm from point O (to the left).
- From point B, there is a force vector \( F \) acting in the direction from B towards the cylindrical structure, angled slightly downward and forward in the \( y \)-direction. This force vector \( F \) is highlighted in blue.
- Point A is on the ground at coordinates (350 mm, 275 mm, 0 mm) relative to point O.
- The horizontal arm at the top of the cylinder is of length 325 mm.
The goal is to determine the moment about the line OB due to this force \( F \). The magnitude of the force \( F \) is given as 600 N.
**Explanation:**
- The moment about a line can be calculated using the vector cross product, considering the position vector of the point where the force is applied and the direction of the force.
- The specific geometry and the given distances are vital for accurately solving for the moment.
This problem requires understanding vector mechanics and may involve breaking down the forces into components, using the cross product to find torque, and integrating the effect of the arm's position relative to point O.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F57103f69-f6d8-477a-b236-0336011ee35d%2F17779001-4f96-42c0-b9fc-67eadcde2370%2Fjv8vae4_processed.png&w=3840&q=75)
Transcribed Image Text:**Q.2) Determine the moment about line OB due to the force F shown in the figure below. The magnitude of force F is 600 N.**
[Image Description]
The diagram illustrates a vertical cylindrical structure with a horizontal arm pivoted at the top. The following points and dimensions are marked:
- The vertical axis is labeled as the \( z \)-axis.
- The horizontal axis perpendicular to \( z \) and going to the left is labeled as the \( x \)-axis.
- The horizontal axis perpendicular to \( z \) and going to the back is labeled as \( y \).
- Point O marks the origin where the vertical cylinder meets the ground.
- Point B is on the \( x \)-axis at a distance of 150 mm from point O (to the left).
- From point B, there is a force vector \( F \) acting in the direction from B towards the cylindrical structure, angled slightly downward and forward in the \( y \)-direction. This force vector \( F \) is highlighted in blue.
- Point A is on the ground at coordinates (350 mm, 275 mm, 0 mm) relative to point O.
- The horizontal arm at the top of the cylinder is of length 325 mm.
The goal is to determine the moment about the line OB due to this force \( F \). The magnitude of the force \( F \) is given as 600 N.
**Explanation:**
- The moment about a line can be calculated using the vector cross product, considering the position vector of the point where the force is applied and the direction of the force.
- The specific geometry and the given distances are vital for accurately solving for the moment.
This problem requires understanding vector mechanics and may involve breaking down the forces into components, using the cross product to find torque, and integrating the effect of the arm's position relative to point O.
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