Q.2) A 50 Kg crate is resting on top of a 40 Kg crate as shown in figure below. The top crate is attached to a wall by a cord, and a rope attached to the bottom crate passes around two fixed pegs. The coefficient of friction between the two crates is 0.35; between the crate and the floor is 0.45; and between the rope and the pegs is 0.3. Determine the minimum force Pmin needed to cause move the bottom crate. 50 Kg 40 Kg

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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**Question 2:**

A 50 Kg crate is resting on top of a 40 Kg crate as shown in the figure below. The top crate is attached to a wall by a cord, and a rope attached to the bottom crate passes around two fixed pegs. The coefficient of friction between the two crates is 0.35; between the crate and the floor is 0.45; and between the rope and the pegs is 0.3. Determine the minimum force \( P_{\text{min}} \) needed to cause move the bottom crate.

**Diagram Explanation:**

The diagram accompanying the question displays two stacked crates, with the upper crate weighing 50 Kg and the lower crate weighing 40 Kg. The upper crate is secured by a cord to a wall, which prevents it from moving. A rope attached to the lower crate is routed around two fixed pegs, forming a loop. A force \( P \) is applied horizontally on the rope to move the lower crate. 

Key elements from the diagram include:

- The 50 Kg crate is on top of the 40 Kg crate.
- A cord attaching the top crate to a wall.
- A rope connected to the bottom crate and passing through two fixed pegs.
- Clear labels denoting the weights of the crates: "50 Kg" on the top and "40 Kg" on the bottom.
- The direction of the applied force \( P \) is indicated horizontally towards the left.
Transcribed Image Text:**Question 2:** A 50 Kg crate is resting on top of a 40 Kg crate as shown in the figure below. The top crate is attached to a wall by a cord, and a rope attached to the bottom crate passes around two fixed pegs. The coefficient of friction between the two crates is 0.35; between the crate and the floor is 0.45; and between the rope and the pegs is 0.3. Determine the minimum force \( P_{\text{min}} \) needed to cause move the bottom crate. **Diagram Explanation:** The diagram accompanying the question displays two stacked crates, with the upper crate weighing 50 Kg and the lower crate weighing 40 Kg. The upper crate is secured by a cord to a wall, which prevents it from moving. A rope attached to the lower crate is routed around two fixed pegs, forming a loop. A force \( P \) is applied horizontally on the rope to move the lower crate. Key elements from the diagram include: - The 50 Kg crate is on top of the 40 Kg crate. - A cord attaching the top crate to a wall. - A rope connected to the bottom crate and passing through two fixed pegs. - Clear labels denoting the weights of the crates: "50 Kg" on the top and "40 Kg" on the bottom. - The direction of the applied force \( P \) is indicated horizontally towards the left.
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