Q.1:Choose the correct answer: (5) V4-x² (1) The domain of the function f (x, y) is the set: y2+1 (b){(x, y)| – 2 < x < 2} (a){(x, y)| – 2< x < 2, y # -1} (d}{(x, y)| – 2 < x < 2, y > 0}. (c){(x,y)| – 2 < x < 2} (2)The range of the function f (x, y) = /9 – x² – y² is: V (a) [3,0). (b) [3,0] ( c) (3, 0] . ( d)[3, –3] (3)The limit of f(x, y) = e*-y at (x, y) → (0,0) along y axis is: (a) 1 (b) –1 (c) 0 ( d) .
Q.1:Choose the correct answer: (5) V4-x² (1) The domain of the function f (x, y) is the set: y2+1 (b){(x, y)| – 2 < x < 2} (a){(x, y)| – 2< x < 2, y # -1} (d}{(x, y)| – 2 < x < 2, y > 0}. (c){(x,y)| – 2 < x < 2} (2)The range of the function f (x, y) = /9 – x² – y² is: V (a) [3,0). (b) [3,0] ( c) (3, 0] . ( d)[3, –3] (3)The limit of f(x, y) = e*-y at (x, y) → (0,0) along y axis is: (a) 1 (b) –1 (c) 0 ( d) .
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Q.1:Choose the correct answer: (5)
V4-x2
(1) The domain of the function f (x,y)
is the set:
y2+1
(c){(x,y)| – 2 < x < 2}
(a){(x, y)| – 2 < x < 2, y # -1}
(d){(x, y)| – 2 < x < 2, y > 0}.
(b){(x,y)| – 2 < x< 2}
(2)The range of the function f(x, y) = /9 – x² – y² is:
-
(a) [3,0).
(b) [3,0]
( c) (3, 0]
( d)[3, –3]
(3)The limit of f (x, y) = e*-y at (x, y) → (0,0) along y axis is:
(a) 1
(b) -1
(c) 0
(d) o.
(4) Let f(x, y, z) = In. Then f2(x, y, z) is:
yz
(a)
yz2
(b)-을 (c) 글
(d) )
yz3
z2
(5) Suppose that f (x, y) has continuous second - order partial derivatives everywhere and
(0,0) is a critical point .If f(0,0)xx = 3, f (0,0)xy = 2, f (0,0),yy = 2, then f (0,0) is
(a) maximum value (b) Minimum value
(c) saddle point (d) test fails.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4afca048-8033-409d-a44e-c4c6ee57f05d%2F03184160-5034-4444-9971-392dc5dfac85%2Ffw8c58p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q.1:Choose the correct answer: (5)
V4-x2
(1) The domain of the function f (x,y)
is the set:
y2+1
(c){(x,y)| – 2 < x < 2}
(a){(x, y)| – 2 < x < 2, y # -1}
(d){(x, y)| – 2 < x < 2, y > 0}.
(b){(x,y)| – 2 < x< 2}
(2)The range of the function f(x, y) = /9 – x² – y² is:
-
(a) [3,0).
(b) [3,0]
( c) (3, 0]
( d)[3, –3]
(3)The limit of f (x, y) = e*-y at (x, y) → (0,0) along y axis is:
(a) 1
(b) -1
(c) 0
(d) o.
(4) Let f(x, y, z) = In. Then f2(x, y, z) is:
yz
(a)
yz2
(b)-을 (c) 글
(d) )
yz3
z2
(5) Suppose that f (x, y) has continuous second - order partial derivatives everywhere and
(0,0) is a critical point .If f(0,0)xx = 3, f (0,0)xy = 2, f (0,0),yy = 2, then f (0,0) is
(a) maximum value (b) Minimum value
(c) saddle point (d) test fails.
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