Q.1 For the two- dimensional element normal stresses ox and oy and shear stress txy is acting as shown in figure below. For the plane 'EF' which makes angle 'O' form horizontal, prove that normal stress (on) and shear stress (tn) at this plane is equal to: Oy + Ox, Oy – Ox - cos 20+ txy sin 20 2 2 Oy – Ox sin 20 – Txy Cos 20 2 Tn =
Q.1 For the two- dimensional element normal stresses ox and oy and shear stress txy is acting as shown in figure below. For the plane 'EF' which makes angle 'O' form horizontal, prove that normal stress (on) and shear stress (tn) at this plane is equal to: Oy + Ox, Oy – Ox - cos 20+ txy sin 20 2 2 Oy – Ox sin 20 – Txy Cos 20 2 Tn =
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Q.1 For the two- dimensional element normal stresses Ox and oy and shear stress txy is acting as
shown in figure below. For the plane 'EF' which makes angle '0' form horizontal, prove that
normal stress (on) and shear stress (Tn) at this plane is equal to:
Oy + Ox, Oy – Ox
On =
2
cos 20+ Tyy sin 20
2
Oy - Ox
-sin 20 – Txy cos 20
2
Tn =
N
Tyx
Txy
B
E](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F005e857a-6b2c-4e9e-ac9d-82c657579c03%2F305b20cf-7415-4f1f-be7d-6f51ad3ed558%2Fyvlktvq_processed.png&w=3840&q=75)
Transcribed Image Text:Q.1 For the two- dimensional element normal stresses Ox and oy and shear stress txy is acting as
shown in figure below. For the plane 'EF' which makes angle '0' form horizontal, prove that
normal stress (on) and shear stress (Tn) at this plane is equal to:
Oy + Ox, Oy – Ox
On =
2
cos 20+ Tyy sin 20
2
Oy - Ox
-sin 20 – Txy cos 20
2
Tn =
N
Tyx
Txy
B
E
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