Q.1\ A. For the following pairs of equations of lines, solve to state whether they are parallel, perpendicular, or skew: L₁: x=-2+t, L₂: x= 3-t, L₁ x = 1+ 4t, L₂: x=2+ 8t, iii. L₁: x = 2t, L₂: i. ii. ==t, 3 X= y = 3 + 2t, y = 4-2t, y = 5 - 4t, y = 4 - 3t, y = 1-t, y=2-t, z = 1+ t z = 4-t z = t z = 1+ 5t z = 5+t z = 2+t
Q.1\ A. For the following pairs of equations of lines, solve to state whether they are parallel, perpendicular, or skew: L₁: x=-2+t, L₂: x= 3-t, L₁ x = 1+ 4t, L₂: x=2+ 8t, iii. L₁: x = 2t, L₂: i. ii. ==t, 3 X= y = 3 + 2t, y = 4-2t, y = 5 - 4t, y = 4 - 3t, y = 1-t, y=2-t, z = 1+ t z = 4-t z = t z = 1+ 5t z = 5+t z = 2+t
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question

Transcribed Image Text:Q.1\ A. For the following pairs of equations of lines, solve to state whether they are
parallel, perpendicular, or skew:
i.
ii.
iii.
L₁: x=2+t,
L₂: x= 3-t,
L₁: x = 1 + 4t,
L₂:
x=2+8t,
L₁:
x = 2t,
L₂:
x = = t₁
z = 4-t
y = 3 + 2t,
y = 4 - 2t,
y = 5 - 4t,
y = 4 - 3t,
y = 1-t,
y=2-²t, z=1+²t
3
z = t
z = -1 + 5t
z = 5+t
z = 2+t
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