Q.1 -8 K, for HCO3 = 2.38 × 10 Calculate Ka for the conjugate acid ( H;CO3) For the reaction : H2CO3(aq) + H2O(aq) = HCO3 (aq) + H3O(aq)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Q.1
-8
K, for HCO3 = 2.38 × 10
Calculate Ka for the conjugate acid ( H¿CO;)
For the reaction :
H2CO3(aq) + H2O(aq) > HCO3 (aq) + H3O*(aq)
Q.2
The molar solubility for Mg3(PO4)2 is 3.5 × 10“M.
Calculate the K, of Mg:(PO4)2 for the reaction:
sp
3-
Mg:(PO4)2 (s) = 3 Mg* (aq) + 2PO," (aq)
The K, expression is:
Kg = [Mg²* }³ [PO4³ ?
%3D
II
Transcribed Image Text:Homework 1.docx > Q.1 -8 K, for HCO3 = 2.38 × 10 Calculate Ka for the conjugate acid ( H¿CO;) For the reaction : H2CO3(aq) + H2O(aq) > HCO3 (aq) + H3O*(aq) Q.2 The molar solubility for Mg3(PO4)2 is 3.5 × 10“M. Calculate the K, of Mg:(PO4)2 for the reaction: sp 3- Mg:(PO4)2 (s) = 3 Mg* (aq) + 2PO," (aq) The K, expression is: Kg = [Mg²* }³ [PO4³ ? %3D II
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