Q.) What is the equilibrium constant for the following reaction if the reaction is reversed and doubled? N₂(g) + 3H₂(g) <-> 2NH3(g) K= 4.2 x 10-²

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**Q.) What is the equilibrium constant for the following reaction if the reaction is reversed and doubled?**

\[ \text{N}_2(g) + 3\text{H}_2(g) \leftrightarrow 2\text{NH}_3(g) \quad K = 4.2 \times 10^{-2} \]

Options:
- A. \( 2.4 \times 10^{7} \)
- B. \( 5.7 \times 10^{2} \)
- C. \( 4.2 \times 10^{-4} \)
- D. \( 8.2 \times 10^{5} \)
- E. \( 2.0 \times 10^{-3} \) 

**Source:** Mississippi State University - Supplemental Instruction

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Transcribed Image Text:**Old Exam Questions** **Q.) What is the equilibrium constant for the following reaction if the reaction is reversed and doubled?** \[ \text{N}_2(g) + 3\text{H}_2(g) \leftrightarrow 2\text{NH}_3(g) \quad K = 4.2 \times 10^{-2} \] Options: - A. \( 2.4 \times 10^{7} \) - B. \( 5.7 \times 10^{2} \) - C. \( 4.2 \times 10^{-4} \) - D. \( 8.2 \times 10^{5} \) - E. \( 2.0 \times 10^{-3} \) **Source:** Mississippi State University - Supplemental Instruction --- **No graphs or diagrams are present in the image.**
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