Q. No. 10. Design a clamper to perform the function indicated in figure given below. Sificon Diodes 10 v 2.7 v -10 v 17.3 v Answer:

Design a clipping circuit that will limit the output voltage to 5V when applying an input sinusoidal waveform with a peak value of 10V. Assume available diodes with voltage drop of 0.5V. Sketch the output waveform of the circuit.

For each circuit shown below, the input v, is a 60HZ, 12 volt peak sine wave. Sketch the waveform resulting at vo. Assume ideal diodes. What are its positive and negative peak values?

Answr all the questions one by one and solve all the unknown values giving all the correct details Let the last digit of the ID = 9

Describe in detail how diodes work and their common applications. Design a clipper circuit that eliminates the positive portion of an AC waveform as shown below, leaving only the negative half-cycles to appear on the output. State approximations that you used.

3. It is required to design a full-wave rectifier circuit using the circuit shown below to provide an average output vol tage of10 V. find the required turns ratio of the transformer. Assume that a conducting diode has a voltage drop of0.7 V. The ac line vol tage is120 Vrms.

Consider the following circuit diagram. Using practical diode model solve the following items. i. What is the type of rectification in this circuit? ii. Calculate the total peak secondary voltage (Note that “RMS" value is given in the circuit) iii. Sketch the plot of time vs voltage over Load (RL) iv. Find the average voltage over Load. v. Find the maximum current passing over diodes. vi. Find the peak inverse voltage (PIV) over the diodes. vii. Find the minimum fuse current rating for the primary coil. 5:1 D DA 120 V rms D3 D2 RL=10kQ RL out ell lelll

A half-wave recitifier is connected to a 50V AC source. If the load resistance is 100 ohms, find: 1) Max load voltage 2) Average load voltage 3) Max load current 4) Average load current 5) RMS load current 6) PIV rating for diode ...

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Consider a silicon pn junction diode at T 300K. The reverse saturation current is Is = 10-14 A and the ideality factor n = 1. Determine the diode current for a diode voltage of VD = 0.573 V and use that to determine the DC and AC resistance of the diode. RDC = 14.13 k rac = 639 Q RDC = 234 Q2 = rac=8Q RDC = 7.00 KQ rac = 307 Q RDC = 1.43 kQ rac = 58 Q