Q. I Determine the moments at A, B, and C, then draw the moment diagram for the beam. The moment of inertia of each span is indicated. Assume support at B is a roller and A and C are fixed. E = 29(10³) ksi. 800 lb/ft LAB = 900 in¹ 24 ft 30 k B Inc=1200 in -8 ft-8 ft- Figure I

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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solve using

Moment Distribution Method

and table.
Please use the procedure of analysis method given. 
nb please: The construction of the shear and moment diagrams must be done using the relationship 
between load, shears, and moments

Method
The following procedure provides a method of analysis of continuous beams by the moment
distribution method:
1. Calculate the distribution factors. At each joint that is free to rotate, calculate the
distribution factor for each of the members rigidly connected to the joint. The distribution
factor for a member end is computed by dividing the relative bending stiffness (I/L) of the
member by the sum of the relative bending stiffness of all the members rigidly connected
to the joint. The sum of the distribution factors at a joint must equal 1.
2. Compute the fixed-end moments. Assuming that all the free joints are clamped against
rotation, evaluate, for each member, the fixed-end moments due to the external loads
and support settlements (if any) by using the fixed-end moment expressions given. The
clockwise fixed-end moments are considered to be positive.
3. Balance the moments at all the joints that are free to rotate applying the moment-
distribution process as follows:
a. At each joint, evaluate the unbalanced moment and distribute the unbalanced
moment to the members connected to the joint. The undistributed moment at
each member end rigidly connected to the joint is obtained by multiplying the
negative of the unbalanced moment by the distribution factor for the member end.
b. Carry over one-half of each distributed moment to the opposite (far) end of the
member.
c. Repeat step 3(a) and 3(b) until either all the free joints are balanced or unbalanced
moments at these joints are negligibly small.
4. Determine the final member end moments by algebraically summing the fix-end moment
and all the distributed and carryover moments at each member end. If the moment
distribution has been carried out correctly, then the final moments must satisfy the
equations of moment equilibrium at all the joints of the structure that are free to rotate.
5. Compute the member end shears by considering the equilibrium of the members of the
structure.
6. Determine support reactions by considering the equilibrium of the joints of the structure.
7. Draw the shear and bending moment diagrams by using the beam sign convention.
Transcribed Image Text:Method The following procedure provides a method of analysis of continuous beams by the moment distribution method: 1. Calculate the distribution factors. At each joint that is free to rotate, calculate the distribution factor for each of the members rigidly connected to the joint. The distribution factor for a member end is computed by dividing the relative bending stiffness (I/L) of the member by the sum of the relative bending stiffness of all the members rigidly connected to the joint. The sum of the distribution factors at a joint must equal 1. 2. Compute the fixed-end moments. Assuming that all the free joints are clamped against rotation, evaluate, for each member, the fixed-end moments due to the external loads and support settlements (if any) by using the fixed-end moment expressions given. The clockwise fixed-end moments are considered to be positive. 3. Balance the moments at all the joints that are free to rotate applying the moment- distribution process as follows: a. At each joint, evaluate the unbalanced moment and distribute the unbalanced moment to the members connected to the joint. The undistributed moment at each member end rigidly connected to the joint is obtained by multiplying the negative of the unbalanced moment by the distribution factor for the member end. b. Carry over one-half of each distributed moment to the opposite (far) end of the member. c. Repeat step 3(a) and 3(b) until either all the free joints are balanced or unbalanced moments at these joints are negligibly small. 4. Determine the final member end moments by algebraically summing the fix-end moment and all the distributed and carryover moments at each member end. If the moment distribution has been carried out correctly, then the final moments must satisfy the equations of moment equilibrium at all the joints of the structure that are free to rotate. 5. Compute the member end shears by considering the equilibrium of the members of the structure. 6. Determine support reactions by considering the equilibrium of the joints of the structure. 7. Draw the shear and bending moment diagrams by using the beam sign convention.
Q. I Determine the moments at A, B, and C, then draw the moment diagram for the beam.
The moment of inertia of each span is indicated. Assume support at B is a roller and A
and C are fixed. E = 29(10³) ksi.
A
800 lb/ft
LAB = 900 inª
24 ft
30 k
I
IBC= 1200 in
|_8 ft_8 ft_
Figure I
Transcribed Image Text:Q. I Determine the moments at A, B, and C, then draw the moment diagram for the beam. The moment of inertia of each span is indicated. Assume support at B is a roller and A and C are fixed. E = 29(10³) ksi. A 800 lb/ft LAB = 900 inª 24 ft 30 k I IBC= 1200 in |_8 ft_8 ft_ Figure I
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