Q. 8: How can we calculate the equations of motion for constant forces?
Q: The three diagrams below show a block of mass m being pulled or pushed at constant acceleration ax…
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Q: TE₂ on planet'
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Q: Q3: Write down the equation of motion of a mass m constrained to move along the parabola y = x2.…
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Q: A catapult fires an object of 0.025 kg into the air at a velocity of 65 m/s at an angle of 30…
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Q: A block swings on a string after being released from rest. When the string becomes vertical it…
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Q: Two masses M1 (3kg) and M2 (1kg) are set up as shown in the attached diagram. The coefficient of…
A: (a) Draw the free-body diagram of both the blocks.
Q: . A man on the edge of a platform 8 ft above the ground throws a ball vertically upwards with an…
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Q: Draw two force diagrams. One for the cart and one for the hanger. You can treat the track as…
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Q: A hammer of mass m = 0.455 kg is moving horizontally at a velocity of v = 6.5 m/s when it strikes a…
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Q: Find the magnitude of the force of tension in strings 1 and 2.
A: Given: A block of mass m is connected with two strings. String 1 makes an angle 60° with horizontal…
Q: A projectile is launched from point A with speed vo= 39 m/s. Determine the value of the launch angle…
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Q: A 800 kg vehicle is traveling at a constant speed of 1.48 m/s due north. What is the total force (in…
A: The objective of the question is to find the total force on the vehicle when it is moving due north…
Q: Topic: You find yourself trapped in the middle of a large frozen lake. Assume the ice has no…
A: In a given situation a person trapped in a middle of large frozen lake. Friction is not present in…
Q: A car is a height of 1.6 meters and width of 2 meters. (the length is immaterial). The following is…
A: The drag force on the car can be calculated using the drag equation:Where: is the drag force. is…
Q: A 2.00 kg stone is sliding to the right on a frictionless horizontal surface at 5.00 m/s when it is…
A: 6.25m/s3.75m/sAlso find the detailed solution of the problemExplanation:Detailed explanation:
Q: How do you solve this? A particle of mass m is moving in the +x direction, and is subject to a…
A: Force in positive x - direction,Fx(v) = - bv2 ------>(1)Where b a is constant. The mass of…
Q: F2 = 1.96 N 90° Fs = 0.98 N, 1450 F1 =1.47 N, 30° 180° E = 3.30 N, 262° In an experiment about…
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Q: Mike uses a block sliding down an inclined plane to estimate the coefficient of kinetic friction,…
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Q: Coulomb constant, k = 8.987 × 10° N · m² /C2. Vacuum permitivity, €o = 8.854 × 10-12 F/m. Magnitude…
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Q: The following information pertains to questions 1, 2, and 3. A workman pulls a sled across an…
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Q: Part A J T= 60 kg 100 kg What is the tension in the rope of the figure? (Figure 1) Express your…
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Q: When a 60 kg skier first starts to be pulled up the ski hill by an old school T-bar, she undergoes a…
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Q: Two horizontal forces, P and Q, are acting on a block that is placed on a table. We know that P =…
A: Given: The mass of the object is 5.1 kg. P→=-2.1i^+4.25k^ N The velocity of the object is constant.
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- A massless spring with spring constant 26 N/m hangs vertically. A body of mass 1.0 kg is attached to its free end and then released. Assume that the spring was unstretched before the body was released. Find how far below the initial position the body descends. I don't understand why I'm getting this first part wrong specifically because the formula is just x= mg/k because F=kx.60° 30° A 50 kg truck engine is lifted using the setup shown. Assuming that the pulleys are frictionless, What force P must be applied to the cable to hold the engine in the position shown with d= 1m? (Hint: because the frictionless pulleys, the tension in the cable will be uniform through out the whole length of the cable.) 2. 3. d 30 kg 600 N/m A 3m 3m Determine the reactions at A and B. 50 kgPlease don't provide handwritten solution....
- A skier slides straight down an incline of 25 degrees without using her poles. The slope itself is 96 meters long, and the skier starts from rest at the top. What would the velocity of the skier be at the bottom of the incline if friction can be neglected? What would your answer be to the previous question if the coefficient of kinetic friction between the skis and the snow is 0.13 on the incline? Upon reaching the bottom of the incline in part b, she reaches a flat portion, and decides to just let friction slow her to a stop. How far does the skier travel along the horizontal portion before coming to a stop, if the coefficient of kinetic friction is 0.28 on the flat portion?9d. Consider the motion of a ball thrown vertically upward. Use a vertical y-axis with the positive direction pointing up. Ignore the air resistance. Draw a force diagram for the ball on its way down. Draw the vectors starting at the black dot. The location and orientation of the vectors will be graded. The length of the vectors will not be graded.The diagram shows overhead views of four situations in which forces act on a block that slides on a frictionless ice surface. In which situations would it be possible for the block to move along the floor with a constant velocity? (Assume the magnitudes of the forces can be adjusted slightly). I do not understand this at all. I know gravitational force is downwards, and frictional force is opposing the pushing force, but how do I solve this?
- 2. A block of mass m is moving with speed v along a horizontal surface when it collides with a uniform rod of mass 2m and length L attached at one end to a pivot. The surface and pivot have negligible friction. The rod is vertical when the block collides with the end of the rod. The block sticks to the rod, and the block-rod system rotates so that the end of the rod reaches a height h, as shown above. The total rotational inertia of the rod about the pivot is 2mL/3. Express answers in parts (a), (b), and (c) in terms of m, L, v, and physical constants as appropriate. 2m, L a. Derive an expression for the angular speed of the block-rod system immediately after the collision. b. Show that the change in height h of the bottom of the rod can be given by the equation A = 3v-/20g. c. Derive an expression for the mechanical energy dissipated during the collision.Solve D,E, FSketch the correct direction of the acceleration vector a⃗ a→ for the system shown in (Figure 1). Sketch the correct direction of the velocity vector v⃗ v→. Select the correct description of a real object for which this is the correct free-body diagram. A ball rolling down a hill. A car is skidding up an embankment. A climber climbs up the Everest mountain. A box resting on an inclined surface.
- A 5.0 kg object has a set of three forces acting on it, as shown in the diagram. At t = 0, the object is located at the origin and is at rest. a) Use Newton’s second law to find the acceleration of the object. Give both the magnitude and the direction (relative to the +x axis). b) What is the velocity of the object at t = 7.50 seconds? Give both the magnitude and the direction (relative to the +x axis). c) How far is the object from the origin at t = 7.50 seconds?Topic: You find yourself trapped in the middle of a large frozen lake. Assume the ice has no friction. All you have on your is warm winter clothing and no way to call/signal for help. You can just barely see the shore in the distance. Use your physics knowledge of Newton's laws to help get you off the lake. Explain your reasoning.