Q. 2) Given the following system of forces acting on the solid as shown, (a) Determine the equivalent force system consisting of a resultant force and a moment (couple moment) acting at point A. (b) Find the simplest resultant force system (a single force) equivalent to the original system. Specify the resultant force in Cartesian vector notation and the location where it's line of action intersects the x- and y- axes. Sketch the line of action of the simplest resultant showing its x- and y-intercepts. 120 N 15° 200 N y 520 mm E F 50 mm 42 Nom 50 mm ΤΑ 240 mm D 70⁰ 40 N-m 640 mm C FR = 252.21-244.6ĵ N MA-93.43k N-m x = 382 mm ỹ = 370 mm 80 N 100 N 180 mm B 50 mm

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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**Question 2:**

Given the following system of forces acting on the solid as shown:

**(a)** Determine the equivalent force system consisting of a resultant force and a moment (couple moment) acting at point A.

**(b)** Find the simplest resultant force system (a single force) equivalent to the original system. Specify the resultant force in Cartesian vector notation and the location where its line of action intersects the x- and y-axes. Sketch the line of action of the simplest resultant showing its x- and y-intercepts.

**Solution Components:**
- Resultant Force (\( \vec{F}_R \)): \( 252.2\hat{i} - 244.6\hat{j} \) N
- Moment about point A (\( M_A \)): \( -93.43\hat{k} \) N·m
- X-intercept (\( \bar{x} \)): 382 mm
- Y-intercept (\( \bar{y} \)): 370 mm

**Diagram Description:**
The diagram represents a rigid body subject to several forces and moments. It includes labeled points (A, C, D, E, F, G), force vectors (e.g., 200 N, 120 N, 80 N, 100 N), distances between points, and moments (e.g., 42 N·m and 40 N·m).

**Important Measurements:**
- AF = 50 mm
- AG = 520 mm
- DE = 240 mm

The force vectors are applied at various angles, and the couple moments at specific points introduce rotational effects. The task involves calculating a single resultant force and determining where its line of action intersects the coordinate axes, providing a simplified representation of the force and moment system.
Transcribed Image Text:**Question 2:** Given the following system of forces acting on the solid as shown: **(a)** Determine the equivalent force system consisting of a resultant force and a moment (couple moment) acting at point A. **(b)** Find the simplest resultant force system (a single force) equivalent to the original system. Specify the resultant force in Cartesian vector notation and the location where its line of action intersects the x- and y-axes. Sketch the line of action of the simplest resultant showing its x- and y-intercepts. **Solution Components:** - Resultant Force (\( \vec{F}_R \)): \( 252.2\hat{i} - 244.6\hat{j} \) N - Moment about point A (\( M_A \)): \( -93.43\hat{k} \) N·m - X-intercept (\( \bar{x} \)): 382 mm - Y-intercept (\( \bar{y} \)): 370 mm **Diagram Description:** The diagram represents a rigid body subject to several forces and moments. It includes labeled points (A, C, D, E, F, G), force vectors (e.g., 200 N, 120 N, 80 N, 100 N), distances between points, and moments (e.g., 42 N·m and 40 N·m). **Important Measurements:** - AF = 50 mm - AG = 520 mm - DE = 240 mm The force vectors are applied at various angles, and the couple moments at specific points introduce rotational effects. The task involves calculating a single resultant force and determining where its line of action intersects the coordinate axes, providing a simplified representation of the force and moment system.
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